There's an existing function that ends in the following, where d is a dictionary:

return d.iteritems()

that returns an unsorted iterator for a given dictionary. I would like to return an iterator that goes through the items sorted by key. How do I do that?

解決方案

Haven't tested this very extensively, but works in Python 2.5.2.

>>> d = {"x":2, "h":15, "a":2222}

>>> it = iter(sorted(d.iteritems()))

>>> it.next()

('a', 2222)

>>> it.next()

('h', 15)

>>> it.next()

('x', 2)

>>>

If you are used to doing for key, value in d.iteritems(): ... instead of iterators, this will still work with the solution above

>>> d = {"x":2, "h":15, "a":2222}

>>> for key, value in sorted(d.iteritems()):

>>> print(key, value)

('a', 2222)

('h', 15)

('x', 2)

>>>

With Python 3.x, use d.items() instead of d.iteritems() to return an iterator.

總結

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