PAT (Advanced Level) 1035. Password (20)
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PAT (Advanced Level) 1035. Password (20)
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簡單題。
#include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> #include<queue> #include<vector> using namespace std;int n; struct X {string a;string b;bool flag; } s[1000+10];int main() {scanf("%d",&n);int fail=0;for(int i=1; i<=n; i++){cin>>s[i].a>>s[i].b;s[i].flag=0;for(int j=0; j<s[i].b.length(); j++){if(s[i].b[j]=='1') s[i].flag=1,s[i].b[j]='@';if(s[i].b[j]=='0') s[i].flag=1,s[i].b[j]='%';if(s[i].b[j]=='l') s[i].flag=1,s[i].b[j]='L';if(s[i].b[j]=='O') s[i].flag=1,s[i].b[j]='o';}fail=fail+s[i].flag;}if(fail==0){if(n==1||n==0) printf("There is %d account and no account is modified\n",n);else printf("There are %d accounts and no account is modified\n",n);}else{printf("%d\n",fail);for(int i=1; i<=n; i++){if(s[i].flag==0) continue;cout<<s[i].a<<" "<<s[i].b<<endl;}}return 0; }?
轉載于:https://www.cnblogs.com/zufezzt/p/5519253.html
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