拓撲圖： 配置參數： R1：

access-list 10 permit 192.168.5.0 0.0.0.255?//配置匹配的流量 route-map ospf permit 10?//創建一個路由圖配置要匹配的流量

match ip address 10??//關聯要匹配的流量 set metric 1?//設置匹配流量的度量值為1 route-map ospf permit 20?//接著用上面的路由圖，配置序號為20，設置其它的流量

set metric 2//設置其它的流量的度量值為2 router ospf 1

redistribute rip subnets//在OSPF里重發布RIP，讓R4可以學習到 network 192.168.3.0 0.0.0.255 area 0

router rip

version 2

redistribute ospf 1 route-map ospf//在RIP里重發布OSPF，并應用上面配置好的路由圖，達到?分流（兩臺設備[R1,R3]配置不同的度量值）和熱備（動態路由可以動態感知網絡拓撲的變化，動態的將度量值小的路由裝進路由表）的效果！！！ network 192.168.1.0

no auto-summary

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R2:

access-list 20 permit 192.168.6.0 0.0.0.255

route-map ospf permit 10

match ip address 20

set metric 1

route-map ospf permit 20

set metric 2

router ospf 1

redistribute rip subnets

network 192.168.4.0 0.0.0.255 area 0

router rip

version 2

redistribute ospf 1 route-map ospf

network 192.168.2.0

no auto-summary 測試： r5#sh ip int b Interface??????????????????IP-Address??????OK? Method Status????????????????Protocol FastEthernet0/0????????????192.168.100.2???YES NVRAM??up????????????????????up????? r5#traceroute 192.168.5.1

1 192.168.100.1 1032 msec 20 msec 4 msec

2 192.168.1.2 16 msec 8 msec 60 msec

3 192.168.3.2 32 msec 12 msec * r5#traceroute 192.168.6.1

??1 192.168.100.1 32 msec 16 msec 16 msec

??2 192.168.2.2 12 msec 28 msec 32 msec

??3 192.168.4.2 16 msec 32 msec * r5# 可以看出要去192.168.5.0的網絡走左邊，去192.168.6.0的網絡走右邊！！！

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配置成功后路由表是這樣的： R2: R????192.168.4.0/24 [120/2] via 192.168.2.2, 00:00:17, Ethernet1/1

????????????????????[120/2] via 192.168.1.2, 00:00:11, Ethernet1/0

?????192.168.5.0/32 is subnetted, 1 subnets

R???????192.168.5.1 [120/1] via 192.168.1.2, 00:00:11, Ethernet1/0

?????192.168.6.0/32 is subnetted, 1 subnets

R???????192.168.6.1 [120/1] via 192.168.2.2, 00:00:17, Ethernet1/1

C????192.168.1.0/24 is directly connected, Ethernet1/0

C????192.168.2.0/24 is directly connected, Ethernet1/1

C????192.168.100.0/24 is directly connected, FastEthernet0/0

R????192.168.3.0/24 [120/2] via 192.168.2.2, 00:00:17, Ethernet1/1

????????????????????[120/2] via 192.168.1.2, 00:00:11, Ethernet1/0 可以看出，R2通過R1學習到192.168.5.0并且為1跳，通過R3學習到192.168.6.0并且為1跳。 現在來測試一下，將R1的E0/0（連著R4的接口）down掉，看看會發現什么現象： R1:

r1(config)#int e0/0

r1(config-if)#sh

r1(config-if)#shutdown R2:

r2#sh ip rou

R????192.168.4.0/24 [120/2] via 192.168.2.2, 00:00:12, Ethernet1/1

?????192.168.5.0/32 is subnetted, 1 subnets

R???????192.168.5.1 [120/2] via 192.168.2.2, 00:00:12, Ethernet1/1

?????192.168.6.0/32 is subnetted, 1 subnets

R???????192.168.6.1 [120/1] via 192.168.2.2, 00:00:12, Ethernet1/1

C????192.168.1.0/24 is directly connected, Ethernet1/0

C????192.168.2.0/24 is directly connected, Ethernet1/1

C????192.168.100.0/24 is directly connected, FastEthernet0/0

R????192.168.3.0/24 [120/2] via 192.168.2.2, 00:00:12, Ethernet1/1

r2# 可以看出R2是通過R3學習到的192.168.5.0的路由的，它的跳數為2，R5要去192.168.5.0的路由要走右邊，因為左邊的R1的上連端口down掉了。這樣達到了熱備的效果！！！

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現在把R1的E0/0再開啟，看看會是什么效果： R1: r1(config)#int e0/0

r1(config-if)#no shutdown R2: r2#??SH IP ROU R????192.168.4.0/24 [120/2] via 192.168.2.2, 00:00:05, Ethernet1/1 [120/2] via 192.168.1.2, 00:00:25, Ethernet1/0 192.168.5.0/32 is subnetted, 1 subnets R???????192.168.5.1 [120/1] via 192.168.1.2, 00:00:25, Ethernet1/0

192.168.6.0/32 is subnetted, 1 subnets R???????192.168.6.1 [120/1] via 192.168.2.2, 00:00:05, Ethernet1/1

C????192.168.1.0/24 is directly connected, Ethernet1/0 C????192.168.2.0/24 is directly connected, Ethernet1/1 C????192.168.100.0/24 is directly connected, FastEthernet0/0 R????192.168.3.0/24 [120/2] via 192.168.2.2, 00:00:05, Ethernet1/1 [120/2] via 192.168.1.2, 00:00:25, Ethernet1/0 r2# 可以看出，R2通過動態路由感知到網絡拓撲的變化，動態地學習到了度量值優的路由，然后入進入路由表里！！！
? ? ? 本文轉自810105851 51CTO博客，原文鏈接：http://blog.51cto.com/4708948/1130037，如需轉載請自行聯系原作者

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