英文題目（老師給的原版題目）：

Write a program that converts from 24-hour notation to 12-hour notation.For example,it should convert 14:25 to 2:25 PM.The input is given as two integers.There should be at least three functions,one for input,one to do the conversion,and one for output.Record the AM/PM information as a value of type char,’A’ for AM and ‘P’ for PM.Thus,the function for doing the conversions will have a call-by-reference formal parameter of type char to record whether it is AM or PM.(The function will have other parameters as well.)Include a loop that lets the user repeat this computation for new input values again and again until the user says he wants to end the program.

中文題目（簡單翻譯一下）：

將24小時制轉換為12小時制的程序。例如，它應該將14:25轉換為2:25 PM。輸入是兩個整數。應該至少有三個函數，一個用于輸入，一個用于轉換，一個用于輸出。將AM/PM信息記錄為char類型的值，’ A '表示AM， ’ P '表示PM。因此，用于進行轉換的函數將具有一個char類型的按引用調用形參，以記錄它是AM還是PM。(該函數還有其他參數。)包含一個循環，讓用戶對新的輸入值一次又一次地重復這個計算，直到用戶說他想結束程序。

代碼：

#include <iostream>using namespace std; int time_24_hour,time_24_minute,time_12_hour,time_12_minute;void Input(){cout<<"請輸入時間（24小時制,小時和分鐘之間用空格區分）："<<endl;cin>>time_24_hour;cin>>time_24_minute;if(time_24_minute<0||time_24_hour<0||time_24_hour>24||time_24_minute>60){cout<<"輸入錯誤程序退出！"<<endl;exit(0);} }void Output(){char time_quanyum;if(time_24_hour>=12){time_quanyum='P';}else{time_quanyum='A';}if(time_12_minute<10){cout<<"轉換成12小時制之后的時間為 "<<time_12_hour<<":0"<<time_12_minute<<" "<<time_quanyum<<endl;}else{cout<<"轉換成12小時制之后的時間為 "<<time_12_hour<<":"<<time_12_minute<<" "<<time_quanyum<<endl;} }void Conversion(){if(time_24_hour<=12){time_12_hour=time_24_hour;}else{time_12_hour=time_24_hour-12;}time_12_minute=time_24_minute; }int main() {char choice;do{Input();Conversion();Output();cout<<"是否繼續轉換？（y或n）"<<endl;cin>>choice;if(choice!='y'&&choice!='n'){cout<<"輸入錯誤程序退出！"<<endl;exit(0);}}while(choice=='y');cout<<"退出成功！"<<endl;return 0; }

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