頑強的小白

1031 Hello World for U （20 分）

Given any string of N (≥5) characters, you are asked to form the characters into the shape of U. For example, helloworld can be printed as:
h d
e l
l r
lowo
That is, the characters must be printed in the original order, starting top-down from the left vertical line with n?1?? characters, then left to right along the bottom line with n?2?? characters, and finally bottom-up along the vertical line with n?3?? characters. And more, we would like U to be as squared as possible – that is, it must be satisfied that n?1??=n?3??=max { k | k≤n?2?? for all 3≤n?2??≤N } with n?1??+n?2??+n?3???2=N.

Input Specification:

Each input file contains one test case. Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.

Output Specification:

For each test case, print the input string in the shape of U as specified in the description.

Sample Input:

helloworld!

Sample Output:

h !
e d
l l
lowor

題目解析

拷貝過來 那個U型散了，不會改，腦補吧。
題目內容就是他給你一個單詞（字符串）你要把它輸出為U型，為了讓這個型最好看，需要平衡三個邊的長度，題目那個算兩邊長度的公式好長，但是仔細看就會發現其實只要三個邊長度盡可能三等分就是最好的，如果不能三等分，就把多余的字母放在底部，還有注意題目中兩個邊的長度是和底邊重疊了一個的。
剩下的就是輸出問題了，慢慢來就行了。

代碼實現

#include <cstdio> #include <cstring> using namespace std; int main(){int n1,n2;char word[100];scanf("%s",word);int len=strlen(word);len=len+2;n1=len/3;n2=len-2*n1;for(int i=0;i<n1-1;++i){printf("%c",word[i]);for(int j=0;j<n2-2;++j)printf(" ");printf("%c\n",word[len-3-i]);}for(int i=0;i<n2;++i){printf("%c",word[n1-1+i]);} }

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