文章目錄

• • 1. 題目
  • 2. 解題

1. 題目

Table: Project

+-------------+---------+ | Column Name | Type | +-------------+---------+ | project_id | int | | employee_id | int | +-------------+---------+ 主鍵為 (project_id, employee_id)。 employee_id 是員工表 Employee 表的外鍵。

Table: Employee

+------------------+---------+ | Column Name | Type | +------------------+---------+ | employee_id | int | | name | varchar | | experience_years | int | +------------------+---------+ 主鍵是 employee_id。

編寫一個SQL查詢，報告所有雇員最多的項目。

查詢結果格式如下所示：

Project table: +-------------+-------------+ | project_id | employee_id | +-------------+-------------+ | 1 | 1 | | 1 | 2 | | 1 | 3 | | 2 | 1 | | 2 | 4 | +-------------+-------------+Employee table: +-------------+--------+------------------+ | employee_id | name | experience_years | +-------------+--------+------------------+ | 1 | Khaled | 3 | | 2 | Ali | 2 | | 3 | John | 1 | | 4 | Doe | 2 | +-------------+--------+------------------+Result table: +-------------+ | project_id | +-------------+ | 1 | +-------------+ 第一個項目有3名員工，第二個項目有2名員工。

來源：力扣（LeetCode）
鏈接：https://leetcode-cn.com/problems/project-employees-ii
著作權歸領扣網絡所有。商業轉載請聯系官方授權，非商業轉載請注明出處。

2. 解題

# Write your MySQL query statement below select project_id from Project p group by project_id having count(p.employee_id) =(select count(*) maxnumofEmpfrom Projectgroup by project_idorder by maxnumofEmp desclimit 1)

或者用 all 函數

# Write your MySQL query statement below select project_id from Project p group by project_id having count(p.employee_id) >=all(select count(*) numfrom Projectgroup by project_id)

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