python 等值线图_python – matplotlib等值线图:对数刻度的比例色度级
我建議生成一個(gè)偽色條如下(見(jiàn)解釋說(shuō)明):
import matplotlib.pyplot as plt
import numpy as np
from matplotlib.colors import LogNorm
import matplotlib.gridspec as gridspec
delta = 0.025
x = y = np.arange(0, 3.01, delta)
X, Y = np.meshgrid(x, y)
Z1 = plt.mlab.bivariate_normal(X, Y, 1.0, 1.0, 0.0, 0.0)
Z2 = plt.mlab.bivariate_normal(X, Y, 1.5, 0.5, 1, 1)
Z = 1e6 * (Z1 * Z2)
fig=plt.figure()
#
# define 2 subplots, using gridspec to control the
# width ratios:
#
# note: you have to import matplotlib.gridspec for this
#
gs = gridspec.GridSpec(1, 2,width_ratios=[15,1])
# the 1st subplot
ax1 = plt.subplot(gs[0])
lvls = np.logspace(0,4,20)
CF = ax1.contourf(X,Y,Z,
norm = LogNorm(),
levels = lvls
)
CS = ax1.contour(X,Y,Z,
norm = LogNorm(),
colors = 'k',
levels = lvls
)
#
# the pseudo-colorbar
#
# the 2nd subplot
ax2 = plt.subplot(gs[1])
#
# new levels!
#
# np.logspace gives you logarithmically spaced levels -
# this, however, is not what you want in your colorbar
#
# you want equally spaced labels for each exponential group:
#
levls = np.linspace(1,10,10)
levls = np.concatenate((levls[:-1],np.linspace(10,100,10)))
levls = np.concatenate((levls[:-1],np.linspace(100,1000,10)))
levls = np.concatenate((levls[:-1],np.linspace(1000,10000,10)))
#
# simple x,y setup for a contourf plot to serve as colorbar
#
XC = [np.zeros(len(levls)), np.ones(len(levls))]
YC = [levls, levls]
CM = ax2.contourf(XC,YC,YC, levels=levls, norm = LogNorm())
# log y-scale
ax2.set_yscale('log')
# y-labels on the right
ax2.yaxis.tick_right()
# no x-ticks
ax2.set_xticks([])
plt.show()
這將給你一個(gè)這樣的情節(jié):
編輯
或者,在調(diào)用顏色欄時(shí),使用新的級(jí)別和間距=“比例”選項(xiàng):
>替換這行:
lvls = np.logspace(0,4,20)
用這些:
lvls = np.linspace(1,10,5)
lvls = np.concatenate((lvls[:-1],np.linspace(10,100,5)))
lvls = np.concatenate((lvls[:-1],np.linspace(100,1000,5)))
lvls = np.concatenate((lvls[:-1],np.linspace(1000,10000,5)))
>替換這行:
cbar = plt.colorbar(CF, ticks=lvls, format='%.4f')
有了這個(gè):
cbar = plt.colorbar(CF, ticks=lvls, format='%.2f', spacing='proportional')
你會(huì)結(jié)束這個(gè)情節(jié):
(格式僅更改,因?yàn)樾碌目潭炔恍枰?位小數(shù))
編輯2
如果你想自動(dòng)生成像我使用的級(jí)別,你可以考慮這段代碼:
levels = []
LAST_EXP = 4
N_LEVELS = 5
for E in range(0,LAST_EXP):
levels = np.concatenate((levels[:-1],np.linspace(10**E,10**(E+1),N_LEVELS)))
總結(jié)
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