android builder模式 插件,如何在Kotlin中实现Builder模式?
首先,在大多數情況下,您不需要在Kotlin中使用構建器,因為我們有默認和命名參數 . 這使您可以寫
class Car(val model: String? = null, val year: Int = 0)
并像這樣使用它:
val car = Car(model = "X")
如果你絕對想要使用構建器,那么你可以這樣做:
使構建器成為 companion object 是沒有意義的,因為 object 是單例 . 而是將其聲明為嵌套類(默認情況下在Kotlin中是靜態的) .
將屬性移動到構造函數,以便也可以以常規方式實例化對象(如果不應該將構造函數設為私有),并使用將構建器和委托作為主構造函數的輔助構造函數 . 代碼如下:
class Car( //add private constructor if necessary
val model: String?,
val year: Int
) {
private constructor(builder: Builder) : this(builder.model, builder.year)
class Builder {
var model: String? = null
private set
var year: Int = 0
private set
fun model(model: String) = apply { this.model = model }
fun year(year: Int) = apply { this.year = year }
fun build() = Car(this)
}
}
用法: val car = Car.Builder().model("X").builder()
使用builder DSL可以另外縮短此代碼:
class Car (
val model: String?,
val year: Int
) {
private constructor(builder: Builder) : this(builder.model, builder.year)
companion object {
inline fun build(block: Builder.() -> Unit) = Builder().apply(block).build()
}
class Builder {
var model: String? = null
var year: Int = 0
fun build() = Car(this)
}
}
用法: val car = Car.build { model = "X" }
如果某些值是必需的并且沒有默認值,則需要將它們放在構建器的構造函數中以及我們剛剛定義的 build 方法中:
class Car (
val model: String?,
val year: Int,
val required: String
) {
private constructor(builder: Builder) : this(builder.model, builder.year, builder.required)
companion object {
inline fun build(required: String, block: Builder.() -> Unit) = Builder(required).apply(block).build()
}
class Builder(
val required: String
) {
var model: String? = null
var year: Int = 0
fun build() = Car(this)
}
}
用法: val car = Car.build(required = "requiredValue") { model = "X" }
總結
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