題目鏈接：

http://acm.hdu.edu.cn/showproblem.php?pid=5882

Problem Description Rock-paper-scissors is a zero-sum hand game usually played between two people, in which each player simultaneously forms one of three shapes with an outstretched hand. These shapes are "rock", "paper", and "scissors". The game has only three possible outcomes other than a tie: a player who decides to play rock will beat another player who has chosen scissors ("rock crushes scissors") but will lose to one who has played paper ("paper covers rock"); a play of paper will lose to a play of scissors ("scissors cut paper"). If both players choose the same shape, the game is tied and is usually immediately replayed to break the tie.

Recently, there is a upgraded edition of this game: rock-paper-scissors-Spock-lizard, in which there are totally five shapes. The rule is simple: scissors cuts paper; paper covers rock; rock crushes lizard; lizard poisons Spock; Spock smashes scissors; scissors decapitates lizard; lizard eats paper; paper disproves Spock; Spock vaporizes rock; and as it always has, rock crushes scissors.

Both rock-paper-scissors and rock-paper-scissors-Spock-lizard are balanced games. Because there does not exist a strategy which is better than another. In other words, if one chooses shapes randomly, the possibility he or she wins is exactly 50% no matter how the other one plays (if there is a tie, repeat this game until someone wins). Given an integer N , representing the count of shapes in a game. You need to find out if there exist a rule to make this game balanced.

?

Input The first line of input contains an integer t, the number of test cases. t test cases follow.
For each test case, there is only one line with an integer N?(2≤N≤1000) , as described above.

Here is the sample explanation.

In the first case, donate two shapes as A and B. There are only two kind of rules: A defeats B, or B defeats A. Obviously, in both situation, one shapes is better than another. Consequently, this game is not balanced.

In the second case, donate two shapes as A, B and C. If A defeats B, B defeats C, and C defeats A, this game is balanced. This is also the same as rock-paper-scissors.

In the third case, it is easy to set a rule according to that of rock-paper-scissors-Spock-lizard.

?

Output For each test cases, output "Balanced" if there exist a rule to make the game balanced, otherwise output "Bad".

?

Sample Input 3 2 3 5

?

Sample Output Bad Balanced Balanced Hint:

題意：

問 nnn 個手勢的石頭剪刀布游戲是否能保證出每種手勢勝率都一樣。

題解：

當每種手勢的攻防個數完全相等才能保證平衡，所以容易得出 nnn 是奇數時游戲平衡，否則不平衡。簽到題。

代碼：

#include <cstdio> int main() {int t;scanf("%d",&t);while(t--){int n;scanf("%d",&n);if(n%2==1)printf("Balanced\n");elseprintf("Bad\n");} }

　　

轉載于:https://www.cnblogs.com/TAT1122/p/5879534.html

總結

以上是生活随笔為你收集整理的2016 ACM/ICPC Asia Regional Qingdao Online 1005 Balanced Game的全部內容，希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯，歡迎將生活随笔推薦給好友。