python 5的倍數

Sometimes, we need to find the sum of all integers or numbers that are completely divisible by 3 and 5 up to thousands, since thousands are a too large number that’s why it becomes difficult for us. So, here we will do it in Python programming language that solves the problem in just a few seconds. To solve this problem, we will use the range function. So, before going to find the sum we will learn a little bit about range function.

有時，我們需要找到可以被3和5整除的所有整數或數字的總和，直到數千，因為數千是一個太大的數字，這就是為什么我們很難做到這一點。 因此，在這里，我們將使用Python編程語言來完成此任務，并在幾秒鐘內解決問題。 為了解決這個問題，我們將使用范圍函數。 因此，在找到總和之前，我們將學習一些有關范圍函數的知識。

What is the range function in Python?

Python中的范圍函數是什么？

The range() is a built-in function available in Python. In simple terms, the range allows them to generate a series of numbers within a given interval. This function only works with the integers i.e. whole numbers.

range()是Python中可用的內置函數。 簡而言之，該范圍允許它們在給定間隔內生成一系列數字。 此函數僅適用于整數，即整數。

Syntax of range() function:

range()函數的語法：

range(start, stop, step)

It takes three arguments to start, stop, and step and it depends on users choose how they want to generate a sequence of numbers? By default range() function takes steps of 1.

它需要三個參數來開始 ， 停止和步進 ，并且取決于用戶選擇如何生成數字序列？ 默認情況下， range()函數采用步驟1。

Program:

程序：

# initialize the value of n n=1000 # initialize value of s is zero. s=0 # checking the number is divisible by 3 or 5 # and find their sum for k in range(1,n+1):if k%3==0 or k%5==0: #checking condition s+=k# printing the result print('The sum of the number:',s)

Output

輸出量

The sum of the number: 234168

翻譯自: https://www.includehelp.com/python/find-the-sum-of-all-numbers-below-1000-which-are-multiples-of-3-or-5.aspx

python 5的倍數

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總結

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