C# 简单的颜色渐变算法
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C# 简单的颜色渐变算法
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今天要用到一個顏色漸變的算法,網(wǎng)上看了很多,覺得都太繁瑣,索性自己寫一個。話不多說,直接上代碼!
**這是用來獲取某一顏色段的分度集合**/// <summary>/// 獲得某一顏色區(qū)間的顏色集合/// </summary>/// <param name="sourceColor">起始顏色</param>/// <param name="destColor">終止顏色</param>/// <param name="count">分度數(shù)</param>/// <returns>返回顏色集合</returns>public static List<Color> GetSingleColorList(Color srcColor, Color desColor, int count){List<Color> colorFactorList = new List<Color>();int redSpan = desColor.R - srcColor.R;int greenSpan = desColor.G - srcColor.G;int blueSpan = desColor.B - srcColor.B;for (int i = 0; i < count; i++){Color color = Color.FromArgb(srcColor.R + (int)((double)i / count * redSpan),srcColor.G + (int)((double)i / count * greenSpan),srcColor.B + (int)((double)i / count * blueSpan));colorFactorList.Add(color);}return colorFactorList;} **這里就是將紅到紫之間的顏色分為5個區(qū)間,利用上面的算法拼接5個區(qū)間的分度值,就得到全彩顏色集合** /// <summary>/// 獲取從紅到紫的顏色段的顏色集合/// </summary>/// <param name="totalCount">分度數(shù)</param>/// <param name="redToPurple">是否從紅到紫色漸變</param>/// <returns>返回顏色集合</returns>public static List<Color> GetFullColorList(int totalCount, bool redToPurple = true){List<Color> colorList = new List<Color>();if (totalCount > 0){if (redToPurple){colorList.AddRange(GetSingleColorList(Color.Red, Color.Yellow, totalCount / 5 + (totalCount % 5 > 0 ? 1 : 0)));colorList.AddRange(GetSingleColorList(Color.Yellow, Color.Lime, totalCount / 5 + (totalCount % 5 > 1 ? 1 : 0)));colorList.AddRange(GetSingleColorList(Color.Lime, Color.Cyan, totalCount / 5 + (totalCount % 5 > 2 ? 1 : 0)));colorList.AddRange(GetSingleColorList(Color.Cyan, Color.Blue, totalCount / 5 + (totalCount % 5 > 3 ? 1 : 0)));colorList.AddRange(GetSingleColorList(Color.Blue, Color.Magenta, totalCount / 5 + (totalCount % 5 > 4 ? 1 : 0)));}else{colorList.AddRange(GetSingleColorList(Color.Magenta, Color.Blue, totalCount / 5 + (totalCount % 5 > 0 ? 1 : 0)));colorList.AddRange(GetSingleColorList(Color.Blue, Color.Cyan, totalCount / 5 + (totalCount % 5 > 1 ? 1 : 0)));colorList.AddRange(GetSingleColorList(Color.Cyan, Color.Lime, totalCount / 5 + (totalCount % 5 > 2 ? 1 : 0)));colorList.AddRange(GetSingleColorList(Color.Lime, Color.Yellow, totalCount / 5 + (totalCount % 5 > 3 ? 1 : 0)));colorList.AddRange(GetSingleColorList(Color.Yellow, Color.Red, totalCount / 5 + (totalCount % 5 > 4 ? 1 : 0)));}}return colorList;}總結(jié)
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