1.合并拆分數組

///?<summary>
????????///?合并數組
????????///?</summary>
????????///?<param?name="First">第一個數組</param>
????????///?<param?name="Second">第二個數組</param>
????????///?<returns>合并后的數組(第一個數組+第二個數組，長度為兩個數組的長度)</returns>
????????public?string[]?MergerArray(string[]?First,?string[]?Second)
????????{
????????????string[]?result?=?new?string[First.Length?+?Second.Length];
????????????First.CopyTo(result,?0);
????????????Second.CopyTo(result,?First.Length);
????????????return?result;
????????}

????????///?<summary>
????????///?數組追加
????????///?</summary>
????????///?<param?name="Source">原數組</param>
????????///?<param?name="str">字符串</param>
????????///?<returns>合并后的數組(數組+字符串)</returns>
????????public?string[]?MergerArray(string[]?Source,?string?str)
????????{
????????????string[]?result?=?new?string[Source.Length?+?1];
????????????Source.CopyTo(result,?0);
????????????result[Source.Length]?=?str;
????????????return?result;
????????}

????????///?<summary>
????????///?從數組中截取一部分成新的數組
????????///?</summary>
????????///?<param?name="Source">原數組</param>
????????///?<param?name="StartIndex">原數組的起始位置</param>
????????///?<param?name="EndIndex">原數組的截止位置</param>
????????///?<returns></returns>
????????public?string[]?SplitArray(string[]?Source,?int?StartIndex,?int?EndIndex)
????????{
????????????try
????????????{
????????????????string[]?result?=?new?string[EndIndex?-?StartIndex+1];
????????????????for?(int?i?=?0;?i?<=?EndIndex?-?StartIndex;?i++)?result[i]?=?Source[i+StartIndex];
????????????????return?result;
????????????}
????????????catch?(IndexOutOfRangeException?ex)
????????????{
????????????????throw?new?Exception(ex.Message);
????????????}
????????}

????????///?<summary>
????????///?不足長度的前面補空格,超出長度的前面部分去掉
????????///?</summary>
????????///?<param?name="First">要處理的數組</param>
????????///?<param?name="byteLen">數組長度</param>
????????///?<returns></returns>
????????public?string[]?MergerArray(string[]?First,?int?byteLen)
????????{
????????????string[]?result;
????????????if?(First.Length?>?byteLen)
????????????{
????????????????result?=?new?string[byteLen];
????????????????for?(int?i?=?0;?i?<?byteLen;?i++)?result[i]?=?First[i?+?First.Length?-?byteLen];
????????????????return?result;
????????????}
????????????else
????????????{
????????????????result?=?new?string[byteLen];
????????????????for?(int?i?=?0;?i?<?byteLen;?i++)?result[i]?=?"?";
????????????????First.CopyTo(result,?byteLen-First.Length);
????????????????return?result;
????????????}
????????}

2.調用

string[]?student1?=?{?"a",?"b",?"c",?"d",?"e",?"f"};
string[]?student2?=?{?"0",?"1",?"2",?"3",?"4",?"5",?"6",?"6",?"1",?"8",?"16",?"10",?"45",?"37",?"82"?};
string?student3?=?"Test";
//兩個數組相加?結果-->?{?"a",?"b",?"c",?"d",?"e",?"f","0",?"1",?"2",?"3",?"4",?"5",?"6",?"6",?"1",?"8",?"16",?"10",?"45",?"37",?"82"?};
string[]?Merger1?=?MergerArray(student1,?student2);
//數組+字符串??結果-->{?"a",?"b",?"c",?"d",?"e",?"f","Test"};
string[]?Merger2?=?MergerArray(student1,?student3);
//不足10位的，前面補空格?結果-->{"?",?"?",?"?",?"?",?"a",?"b",?"c",?"d",?"e",?"f"};
string[]?Merger3?=?MergerArray(student1,?10);
//超過3位的，只取最后3后?結果-->{"d",?"e",?"f"};
string[]?Merger4?=?MergerArray(student1,?3);
//截取部分數組?結果-->{"c",?"d",?"e"};
?string[]?SplitArray1?=?SplitArray(student1,?2,?4);

?

轉載于:https://www.cnblogs.com/dreamszx/archive/2012/09/29/2708558.html

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