題干：

You are given a string?ss?of length?nn, which consists only of the first?kk?letters of the Latin alphabet. All letters in string?ss?are uppercase.

A?subsequence?of string?ss?is a string that can be derived from?ss?by deleting some of its symbols without changing the order of the remaining symbols. For example, "ADE" and "BD" are subsequences of "ABCDE", but "DEA" is not.

A subsequence of?ss?called?good?if the number of occurences of each of the first?kkletters of the alphabet is the same.

Find the length of the longest good subsequence of?ss.

Input

The first line of the input contains integers?nn?(1≤n≤1051≤n≤105) and?kk?(1≤k≤261≤k≤26).

The second line of the input contains the string?ss?of length?nn. String?ss?only contains uppercase letters from 'A' to the?kk-th letter of Latin alphabet.

Output

Print the only integer?— the length of the longest good subsequence of string?ss.

Examples

Input

9 3 ACAABCCAB

Output

6

Input

9 4 ABCABCABC

Output

0

Note

In the first example, "ACBCAB" ("ACAABCCAB") is one of the subsequences that has the same frequency of 'A', 'B' and 'C'. Subsequence "CAB" also has the same frequency of these letters, but doesn't have the maximum possible length.

In the second example, none of the subsequences can have 'D', hence the answer is?00.

解題報告：

? ? 這題還是自己要讀一遍，先解釋了一遍子序列的概念，，這個很有往錯誤的方向誘導(dǎo)。。

? ? 本來想著二分長度做，看數(shù)據(jù)量也剛剛好，但是做的時候發(fā)現(xiàn)根本不需要，其實就是很簡單的一個預(yù)處理就ojbk了。

AC代碼：

#include<bits/stdc++.h>using namespace std; const int MAX = 2e5 + 5; char s[MAX]; int bk[55]; int main() {int n,k;cin>>n>>k;cin>>s;int len = strlen(s);for(int i = 0; i<len; i++) {bk[s[i]-'A']++;}int minn = 0x3f3f3f3f;for(int i = 0; i<k; i++) {minn = min(minn,bk[i]);}cout << minn*k << endl;return 0 ; }//18:04 - 18:17

?

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