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openssl 学习之从证书中提取RSA公钥N 和 E
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原文鏈接:?http://blog.csdn.net/kkxgx/article/details/19850509
通常數字證書包含很多信息，其中N和E值即我們稱為的公鑰。如何從PEM 或者DER格式的證書中提出證書呢？下面給出代碼實現從PEM和DER編碼的證書中提出N、E。
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[cpp]?view plaincopy ? #include?<openssl/evp.h>??#include?<openssl/x509.h>??#include?<stdio.h>??#include?<stdlib.h>??void?PrintHex(unsigned?char?*str,?unsigned?int?len)??{??????int?i?=?0;??????for(i?=0;i<?len;?i++)??????{??????????if(i%4?==?0)??????{?????????printf("0x");??????}??????????printf("%02x",str[i]);??????if(i%4?==?3)??????????{?????????????printf("?");??????????}??????????if(i%16?==?15)??????????{??????????printf("\n");??????????}??????}??????printf("\n");??}??void?GetPukfromPEM()??{??????X509?*x;??????BIO?*b;??????EVP_PKEY?*k;??????RSA?*rsa;??????unsigned?char?n[300]?={0x0};??????unsigned?char?e[300]?={0x0};??????unsigned?int?len;??????????b=BIO_new_file("www.google.com1","r");??????x=PEM_read_bio_X509(b,NULL,NULL,NULL);??????k=X509_get_pubkey(x);??????rsa=EVP_PKEY_get1_RSA(k);??????if(rsa->n?!=?NULL)??????{??????????BN_bn2bin(rsa->n,?n);??????????len=?BN_num_bytes(rsa->n);??????????printf("N:\n");??????????PrintHex(n,len);??????}??????else??????{??????????printf("PEM?error?\n");??????}??????if(rsa->e?!=?NULL)??????{??????????BN_bn2bin(rsa->e,?e);??????????len=?BN_num_bytes(rsa->e);????????????printf("E:\n");??????????PrintHex(e,len);??????}??????else??????{??????????printf("PEM?error?\n");??????}??????BIO_free(b);??????X509_free(x);??}??void?GetPukfromDER()??{??????X509?*x;??????FILE?*fp;??????unsigned?char???buf[5000],*p;??????int?ret;??? ??????EVP_PKEY?*k;??????RSA?*rsa;??????unsigned?char?n[300]?={0x0};??????unsigned?char?e[300]?={0x0};??????unsigned?int?len;??????????fp=fopen("www.google.com2","rb");??????if(!fp)?return?;??????len=fread(buf,1,5000,fp);??????fclose(fp);??????p=buf;??????x=X509_new();??????d2i_X509(&x,(const?unsigned?char?**)&p,len);??????k=X509_get_pubkey(x);??????rsa=EVP_PKEY_get1_RSA(k);??????if(rsa->n?!=?NULL)??????{??????????BN_bn2bin(rsa->n,?n);??????????len=?BN_num_bytes(rsa->n);??????printf("N:\n");??????PrintHex(n,len);??????}??????else??????{??????????printf("DER?error?\n");??????}??????if(rsa->e?!=?NULL)??????{??????????BN_bn2bin(rsa->e,?e);??????????len=?BN_num_bytes(rsa->e);??????????printf("E:\n");??????????PrintHex(e,len);??????}??????else??????{??????????printf("DER?error?\n");??????}??? ? ??????X509_free(x);?????}??int?main()??{??????GetPukfromPEM();??????GetPukfromDER();??????return?0;??}?? 程序執行結果如下：
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[plain]?view plaincopy ? N:??0xb073f0f2?0x04eec2a2?0x46ca342a?0xaabb6023???0xd111761f?0x1f3ad065?0x834e9a45?0xa8437085???0x76f01f87?0x00021f6e?0x3b1717c4?0xb5e91946???0xa292258d?0x622ab463?0x301fb985?0xf835e116???0x5a7649cc?0x50485339?0x5989d684?0x02fb9aec???0x1bc751d5?0x769590d4?0x3a2ab8a6?0xde024d06???0xfbcdeda5?0x46415f55?0x74e5ec7e?0x40dc509c???0xb5e4355d?0x1e6820f8?0xe9dea36a?0x28bf41d2???0xa1b3e225?0x8d0c1bca?0x3d930c18?0xaedfc5bc???0xfdbc82ba?0x6800d716?0x32719f65?0xb511da68???0x59d0a657?0x641bc9fe?0x98e5f5a5?0x65eae1db???0xeef4b39d?0xb38eea87?0xae16d21e?0xa07c7c69???0x3f291685?0x0153a76c?0xf160abdd?0xa2fc2547???0xd432d112?0xddf74812?0xe0fc9ca2?0x7798e989???0x99b8f838?0xf18c06c2?0x7a23366d?0x9b9dcd30???0xc8c73417?0x1ebb7d42?0xc8abe715?0x16f673b5?????E:??0x010001??N:??0xb073f0f2?0x04eec2a2?0x46ca342a?0xaabb6023???0xd111761f?0x1f3ad065?0x834e9a45?0xa8437085???0x76f01f87?0x00021f6e?0x3b1717c4?0xb5e91946???0xa292258d?0x622ab463?0x301fb985?0xf835e116???0x5a7649cc?0x50485339?0x5989d684?0x02fb9aec???0x1bc751d5?0x769590d4?0x3a2ab8a6?0xde024d06???0xfbcdeda5?0x46415f55?0x74e5ec7e?0x40dc509c???0xb5e4355d?0x1e6820f8?0xe9dea36a?0x28bf41d2???0xa1b3e225?0x8d0c1bca?0x3d930c18?0xaedfc5bc???0xfdbc82ba?0x6800d716?0x32719f65?0xb511da68???0x59d0a657?0x641bc9fe?0x98e5f5a5?0x65eae1db???0xeef4b39d?0xb38eea87?0xae16d21e?0xa07c7c69???0x3f291685?0x0153a76c?0xf160abdd?0xa2fc2547???0xd432d112?0xddf74812?0xe0fc9ca2?0x7798e989???0x99b8f838?0xf18c06c2?0x7a23366d?0x9b9dcd30???0xc8c73417?0x1ebb7d42?0xc8abe715?0x16f673b5?????E:??0x010001 ? ?
轉載于:https://www.cnblogs.com/huhu0013/p/4794613.html
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