題目鏈接

Problem Description

Network flow is a well-known difficult problem for ACMers. Given a graph, your task is to find out the maximum flow for the weighted directed graph.

?Input

The first line of input contains an integer T, denoting the number of test cases.
For each test case, the first line contains two integers N and M, denoting the number of vertexes and edges in the graph. (2 <= N <= 15, 0 <= M <= 1000)
Next M lines, each line contains three integers X, Y and C, there is an edge from X to Y and the capacity of it is C. (1 <= X, Y <= N, 1 <= C <= 1000)

?Output

For each test cases, you should output the maximum flow from source 1 to sink N.

Sample Input

2
3 2
1 2 1
2 3 1
3 3
1 2 1
2 3 1
1 3 1
Sample Output

Case 1: 1 Case 2: 2

模板題，用來測試模板，我的模板都能過。

#include<cstdio> #include<cstring> #include<queue> #define INF 1e9 using namespace std; const int maxn=200+5;struct Edge {int from,to,cap,flow;Edge() {}Edge(int f,int t,int c,int flow):from(f),to(t),cap(c),flow(flow) {} };struct Dinic {int n,m,s,t;vector<Edge> edges;vector<int> G[maxn];bool vis[maxn];int cur[maxn];int d[maxn];void init(int n,int s,int t){this->n=n, this->s=s, this->t=t;edges.clear();for(int i=1; i<=n; i++)G[i].clear();}void AddEdge(int from,int to,int cap){edges.push_back(Edge(from,to,cap,0));edges.push_back(Edge(to,from,0,0));m = edges.size();G[from].push_back(m-2);G[to].push_back(m-1);}bool BFS(){memset(vis,0,sizeof(vis));queue<int> Q;d[s]=0;Q.push(s);vis[s]=true;while(!Q.empty()){int x=Q.front();Q.pop();for(int i=0; i<G[x].size(); i++){Edge& e=edges[G[x][i]];if(!vis[e.to] && e.cap>e.flow){vis[e.to]=true;Q.push(e.to);d[e.to]= 1+d[x];}}}return vis[t];}int DFS(int x,int a){if(x==t || a==0)return a;int flow=0,f;for(int& i=cur[x]; i<G[x].size(); i++){Edge& e=edges[G[x][i]];if(d[x]+1==d[e.to] && (f=DFS(e.to,min(a,e.cap-e.flow) ))>0 ){e.flow+=f;edges[G[x][i]^1].flow -=f;flow+=f;a-=f;if(a==0)break;}}return flow;}int Maxflow(){int flow=0;while(BFS()){memset(cur,0,sizeof(cur));flow += DFS(s,INF);}return flow;} } DC;int main() {int n,m,t;scanf("%d",&t);for(int i=1;i<=t;++i){scanf("%d%d",&n,&m);DC.init(n,1,n);while(m--){int u,v,w;scanf("%d%d%d",&u,&v,&w);DC.AddEdge(u,v,w);}printf("Case %d: %d\n",i,DC.Maxflow());}return 0; }

?

總結

以上是生活随笔為你收集整理的网络流--最大流--HDU 3549 Flow Problem的全部內容，希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網(wǎng)站內容還不錯，歡迎將生活随笔推薦給好友。