讀書時(shí)的小測(cè)試題.重新寫一遍 .

可以將出生和當(dāng)前日期定為結(jié)構(gòu)體 這樣傳值就很方便.

#include <stdio.h> #include <math.h> #include <stdbool.h> int leap_year_arr[12] = {31,29,31,30,31,30,31,31,30,31,30,31}; //閏年 int Ordinary_year_arr[12] = {31,28,31,30,31,30,31,31,30,31,30,31}; //平年bool check_is_leap(int year) {if ( year%400==0 ){return true;}else if(year%100!=0 && year%4 == 0){return true;}else{return false;} } int middle_sum(int born,int now) //中間年份日子的計(jì)算 {int middlesum = 0;while (born+1 < now){if(check_is_leap(born+1)){middlesum = middlesum + 366;}else{middlesum = middlesum + 365;}born++;} return middlesum; } int now_past_day(int pyear,int pmount,int pday) //今年已經(jīng)過去多久天 {int sumpastday = 0; //過去的總天數(shù)int mount = 0; //用于累加 去計(jì)算過去幾個(gè)月了;if (check_is_leap(pyear)){while( mount < pmount){sumpastday = sumpastday + leap_year_arr[mount]; //閏年數(shù)組mount ++;}}else{while( mount < pmount){sumpastday = sumpastday + Ordinary_year_arr[mount]; //平年數(shù)組mount ++;}}sumpastday = sumpastday + pday; //還要算上這個(gè)月過去的 return sumpastday; } int have_day(int pyear,int pmount,int pday) //今年還有多少天 {int haveday = 0;if( check_is_leap(pyear)){haveday = 366 - now_past_day(pyear,pmount,pday);}else{haveday = 365 - now_past_day(pyear,pmount,pday);} return haveday; } bool check_entry(int bornyear,int nowyear,int bornmonth,int nowmonth,int bornday, int nowday) {if( bornyear > nowyear || nowmonth > 12 || bornmonth > 12 || bornday > 31 || nowday > 31){printf("您的輸入有誤 請(qǐng)輸入正確值\n");return false;}else if( !check_is_leap(bornyear) && bornday > 28 && bornmonth == 2){printf("您出生年不是閏年 2月份 只有28 天\n");return false;}else if( !check_is_leap(nowyear) && nowday > 28 && nowmonth == 2){printf("現(xiàn)在不是閏年 2月份 只有28 天\n");return false;}else{return true;} } int main() {int bornyear = 0, bornmonth = 0, bornday = 0;int nowyear = 0, nowmonth = 0, nowday = 0;int sumday = 0;printf("請(qǐng)輸入當(dāng)前日期 年--月--日\(chéng)n");scanf("%d%d%d",&nowyear,&nowmonth,&nowday);printf("請(qǐng)輸入出生年份日期 年--月--日\(chéng)n");scanf("%d%d%d",&bornyear,&bornmonth,&bornday);if (check_entry(bornyear,nowyear,bornmonth,nowmonth,bornday,nowday) == false){return 0;}// 總天數(shù)等于出生年還剩多少天 + 現(xiàn)在年過去多少天 + 中間年if( bornyear == nowyear){sumday = have_day(bornyear,bornmonth,bornday) - have_day(nowyear,nowmonth,nowday);}else{sumday = have_day(bornyear,bornmonth,bornday) + now_past_day(nowyear,nowmonth,nowday) + middle_sum(bornyear,nowyear); }printf("你已經(jīng)來到地球%d天\n",sumday + 1); return 0; }

也可以使用時(shí)間戳,這樣就沒上面有意思

#include<stdio.h> #include<time.h> #include<stdlib.h>int main() {char c_born[8] ={0};struct tm* tmp_time = (struct tm*)malloc(sizeof(struct tm));printf("請(qǐng)輸入您的出生年--月--日\(chéng)n");scanf("%s",c_born);strptime(c_born,"%Y%m%d",tmp_time);time_t born_t = mktime(tmp_time); //轉(zhuǎn)化時(shí)間戳//獲取系統(tǒng)的時(shí)間戳time_t nowtime = time(NULL);double day = difftime(nowtime,born_t);//printf("%f\n",difftime(nowtime,t));printf("您來到地球已經(jīng) = %f天\n",day/(60*60*24)); return 0; }

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