PAT B 1044

火星文兩位的時候，個位的0不需要，小坑。（代碼好爛，時間久了，已經不想看了，也不想改了）

#include<stdio.h> #include<string.h> #include<stdlib.h> #include<iostream> using namespace std;char s1[20][10] = { "tret","jan","feb","mar","apr","may","jun","jly","aug","sep","oct","nov","dec" }; char s2[20][10] = { "0","tam","hel","maa","huh","tou","kes","hei","elo","syy","lok","mer","jou" }; char s[10];int main() {int n; char c;scanf("%d", &n);scanf("%c", &c);for (int i = 1; i <= n; i++){gets(s);int a = 0;int l = strlen(s);if (s[0] >= '0'&&s[0] <= '9'){for (int j = 0; j<l; j++){a = a * 10 + (s[j] - '0');}if (a<13)printf("%s\n", s1[a]);else if(a%13==0)printf("%s\n", s2[a / 13 % 13]);elseprintf("%s %s\n", s2[a / 13 % 13], s1[a % 13]);}else{if (s1[0][0] == s[0] && s1[0][1] == s[1] && s1[0][2] == s[2] && s1[0][3] == s[3])a = 0;for (int j = 1; j<13; j++){if (s1[j][0] == s[0] && s1[j][1] == s[1] && s1[j][2] == s[2])a = j;}for (int j = 1; j<13; j++){if (s2[j][0] == s[0] && s2[j][1] == s[1] && s2[j][2] == s[2])a = j * 13;}if (l>3){if (s1[0][0] == s[0] && s1[0][1] == s[1] && s1[0][2] == s[2] && s1[0][3] == s[3])a = 0;for (int j = 1; j<13; j++){if (s1[j][0] == s[4] && s1[j][1] == s[5] && s1[j][2] == s[6])a = a + j;}}cout << a << endl;}}return 0; }

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