select '[2.0]Exploration and Development Department'

--想截取掉[2.0] 只顯示Exploration and Development Department

select right('[2.0]Exploration and Development Department',len('[2.0]Exploration and Development Department')-5)
select SUBSTRING('[2.0]Exploration and Development Department',6,LEN('[2.0]Exploration and Development Department'))

---PB里的寫法是
ls_dept = Right(string(ldw_input.object.dept_index[ll_row]), len(string(ldw_input.object.dept_index[ll_row]))-5)

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