ISP圖像處理開發(fā)過程，需對sensor傳入的bayer圖進(jìn)行處理，包括黑電平校準(zhǔn)、壞點(diǎn)去除，為驗(yàn)證這類型的模塊的功能，仿真階段需要將bayer作為模塊的輸入，此時(shí)需要獲得一幀圖片對應(yīng)的raw data，如txt格式。

可在matlab中編寫程序，獲得RGB圖到bayer圖、bayer圖對應(yīng)txt文件。

Bayer圖包含4種格式RGGB\GRBG\BGGR\GBRG，四種格式對應(yīng)4種txt和bayer圖。

目標(biāo)：RGB圖轉(zhuǎn)成bayer圖、bayer圖對應(yīng)txt文件

實(shí)現(xiàn)：

以4k圖為例，實(shí)現(xiàn)代碼如下，詳情見注釋

%read img,get hang,lie,weidu

????H=imread('pic\4k1.jpeg');%獲得三張矩陣，依次為RGB

????A=double(H);

????[hang,lie,wei]=size(A);%2160,3840,3

% ??G R B G ????

????GRBG=zeros(hang,lie);??????%三維RGB圖轉(zhuǎn)為1維Bayer圖

????for?i=1:2:hang ????????????%G ??輪詢行

????????for?j=1:2:lie ?????????% ???輪詢列

????????????GRBG(i,j)=A(i,j,2);????%讀取G矩陣的數(shù)據(jù)

????????end?

????end

????for?i=1:2:hang ?????%2160 ??R

????????for?j=2:2:lie ??%3840 ??

????????????GRBG(i,j)=A(i,j,1);????%讀取R矩陣的數(shù)據(jù)

????????end?

????end

????for?i=2:2:hang ?????????????%B

????????for?j=1:2:lie ?????

????????????GRBG(i,j)=A(i,j,3);?????%讀取B矩陣的數(shù)據(jù)

????????end?

????end

????for?i=2:2:hang ?????????????%G

????????for?j=2:2:lie ?????

????????????GRBG(i,j)=A(i,j,2);?????%讀取G矩陣的數(shù)據(jù)

????????end?

????end

C1=uint8(GRBG);?????????????????????%8位 0-255

imwrite(C1,'pic\4k1_bayer_GRBG.jpeg');%輸出bayer圖

csvwrite('txt\4k1_bayer_GRBG.txt',C1)?%輸出對應(yīng)txt

% ??R G G B

????RGGB=zeros(hang,lie);

????for?i=1:2:hang ?????%2160 ??R

????????for?j=1:2:lie ??%3840 ??

????????????RGGB(i,j)=A(i,j,1);????

????????end?

????end

????for?i=1:2:hang ????????????%G

????????for?j=2:2:lie ?????

????????????RGGB(i,j)=A(i,j,2);????

????????end?

????end

????for?i=2:2:hang ?????????????%G

????????for?j=1:2:lie ?????

????????????RGGB(i,j)=A(i,j,2);????

????????end?

????end

????for?i=2:2:hang ?????????????%B

????????for?j=2:2:lie ?????

????????????RGGB(i,j)=A(i,j,3);????

????????end?

????end

C2=uint8(RGGB);

imwrite(C2,'pic\4k1_bayer_RGGB.jpeg');

csvwrite('txt\4k1_bayer_RGGB.txt',C2)

% ??B G G R

????BGGR=zeros(hang,lie);

????for?i=1:2:hang ?????????????%B

????????for?j=1:2:lie ?????

????????????BGGR(i,j)=A(i,j,3);????

????????end?

????end

????for?i=1:2:hang ????????????%G

????????for?j=2:2:lie ?????

????????????BGGR(i,j)=A(i,j,2);????

????????end?

????end

????for?i=2:2:hang ?????????????%G

????????for?j=1:2:lie ?????

????????????BGGR(i,j)=A(i,j,2);????

????????end?

????end

????for?i=2:2:hang ?????%3840 ??R

????????for?j=2:2:lie ??%2160 ??

????????????BGGR(i,j)=A(i,j,1);????

????????end?

????end

C3=uint8(BGGR);

imwrite(C3,'pic\4k1_bayer_BGGR.jpeg');

csvwrite('txt\4k1_bayer_BGGR.txt',C3)

% ??G B R G

????GBRG=zeros(hang,lie);

????for?i=1:2:hang ????????????%G

????????for?j=1:2:lie ?????

????????????GBRG(i,j)=A(i,j,2);????

????????end?

????end

????for?i=1:2:hang ?????????????%B

????????for?j=2:2:lie ?????

????????????GBRG(i,j)=A(i,j,3);????

????????end?

????end

????for?i=2:2:hang ?????%3840 ??R

????????for?j=1:2:lie ??%2160 ??

????????????GBRG(i,j)=A(i,j,1);????

????????end?

????end

????for?i=2:2:hang ?????????????%G

????????for?j=2:2:lie ?????

????????????GBRG(i,j)=A(i,j,2);????

????????end?

????end

C4=uint8(GBRG);

imwrite(C4,'pic\4k1_bayer_GBRG.jpeg');

csvwrite('txt\4k1_bayer_GBRG.txt',C4)

subplot(231),imshow(A);

subplot(232),imshow(C1);

subplot(233),imshow(C2);

subplot(234),imshow(C3);

subplot(235),imshow(C4);

實(shí)際效果如下圖

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