最近遇到一個(gè)很蛋疼的問題，用戶如果在客戶端輸入表情可能會(huì)引起一些報(bào)錯(cuò)，在查了一些資料后發(fā)現(xiàn)很多坑人的代碼，我在總結(jié)了之后給出了一個(gè)比較完美的版本。 親測可以判斷絕大多數(shù)表情。 package com.luo.dtqjh.utils;import org.apache.commons.lang.StringUtils;public class EmojiFilter {public static boolean containsEmoji(String source) {int len = source.length();boolean isEmoji = false;for (int i = 0; i < len; i++) {char hs = source.charAt(i);if (0xd800 <= hs && hs <= 0xdbff) {if (source.length() > 1) {char ls = source.charAt(i + 1);int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;if (0x1d000 <= uc && uc <= 0x1f77f) {return true;}}} else {// non surrogateif (0x2100 <= hs && hs <= 0x27ff && hs != 0x263b) {return true;} else if (0x2B05 <= hs && hs <= 0x2b07) {return true;} else if (0x2934 <= hs && hs <= 0x2935) {return true;} else if (0x3297 <= hs && hs <= 0x3299) {return true;} else if (hs == 0xa9 || hs == 0xae || hs == 0x303d|| hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c|| hs == 0x2b1b || hs == 0x2b50 || hs == 0x231a) {return true;}if (!isEmoji && source.length() > 1 && i < source.length() - 1) {char ls = source.charAt(i + 1);if (ls == 0x20e3) {return true;}}}}return isEmoji;}private static boolean isEmojiCharacter(char codePoint) {return (codePoint == 0x0) || (codePoint == 0x9) || (codePoint == 0xA)|| (codePoint == 0xD)|| ((codePoint >= 0x20) && (codePoint <= 0xD7FF))|| ((codePoint >= 0xE000) && (codePoint <= 0xFFFD))|| ((codePoint >= 0x10000) && (codePoint <= 0x10FFFF));}/*** 過濾emoji 或者 其他非文字類型的字符* * @param source* @return*/public static String filterEmoji(String source) {if (StringUtils.isBlank(source)) {return source;}StringBuilder buf = null;int len = source.length();for (int i = 0; i < len; i++) {char codePoint = source.charAt(i);if (isEmojiCharacter(codePoint)) {if (buf == null) {buf = new StringBuilder(source.length());}buf.append(codePoint);}}if (buf == null) {return source;} else {if (buf.length() == len) {buf = null;return source;} else {return buf.toString();}}} }

附上測試代碼

public class Test {

public static void main(String[] args) {String string = "��都嗨��、齊靜��給你��";System.out.println(EmojiFilter.containsEmoji(string));System.out.println(EmojiFilter.filterEmoji(string)); }

}

總結(jié)

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