題目

https://leetcode.com/problems/design-twitter/

題解

這題不難，就是業(yè)務(wù)代碼。。寫就是了。不知道為啥是 medium 題。

class Twitter {public static class Feed {int userId;int tweetId;public Feed(int userId, int tweetId) {this.userId = userId;this.tweetId = tweetId;}}List<Feed> tweetList;Map<Integer, Set<Integer>> followMap;/*** Initialize your data structure here.*/public Twitter() {tweetList = new ArrayList<>();followMap = new HashMap<>();}/*** Compose a new tweet.*/public void postTweet(int userId, int tweetId) {tweetList.add(new Feed(userId, tweetId));}/*** Retrieve the 10 most recent tweet ids in the user's news feed. Each item in the news feed must be posted by users who the user followed or by the user herself. Tweets must be ordered from most recent to least recent.*/public List<Integer> getNewsFeed(int userId) {Set<Integer> follows;if (followMap.containsKey(userId)) {follows = followMap.get(userId);} else {follows = new HashSet<>();}follows.add(userId);ArrayList<Integer> feedList = new ArrayList<>();for (int i = tweetList.size() - 1; i >= 0; i--) {if (follows.contains(tweetList.get(i).userId)) {feedList.add(tweetList.get(i).tweetId);if (feedList.size() == 10) return feedList;}}return feedList;}/*** Follower follows a followee. If the operation is invalid, it should be a no-op.*/public void follow(int followerId, int followeeId) {Set<Integer> followSet;if (!followMap.containsKey(followerId)) {followSet = new HashSet<>();} else {followSet = followMap.get(followerId);}followSet.add(followeeId);followMap.put(followerId, followSet);}/*** Follower unfollows a followee. If the operation is invalid, it should be a no-op.*/public void unfollow(int followerId, int followeeId) {if (followMap.containsKey(followerId)) {followMap.get(followerId).remove(followeeId);}} }/*** Your Twitter object will be instantiated and called as such:* Twitter obj = new Twitter();* obj.postTweet(userId,tweetId);* List<Integer> param_2 = obj.getNewsFeed(userId);* obj.follow(followerId,followeeId);* obj.unfollow(followerId,followeeId);*/

總結(jié)

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