pat 1058 A+B in Hogwarts（20 分）
1058 A+B in Hogwarts（20 分）
If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and Bare given in the standard form of Galleon.Sickle.Knut (Galleon is an integer in [0,10?7??], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).
Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:
3.2.1 10.16.27
Sample Output:
14.1.28#include <iostream>
#include <algorithm>
#include <cstdio>
#include <cstring>
#include <map>
#include <stack>
#include <vector>
#include <queue>
#include <set>
#define LL long long
using namespace std;
const int MAX = 1e7 + ; int a1, a2, b1, b2, c1, c2, ans1 = , ans2 = , ans3 = , b = ; int main()
{
// freopen("Date1.txt", "r", stdin);
scanf("%d.%d.%d %d.%d.%d", &a1, &b1, &c1, &a2, &b2, &c2);
ans3 += (c1 + c2) % , b = (c1 + c2) / ;
ans2 += (b + b1 + b2) % , b = (b + b1 + b2) / ;
ans1 += b + a1 + a2;
printf("%d.%d.%d\n", ans1, ans2, ans3);
return ;
}
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