C#模擬MSN窗體抖動

窗體抖動是件很有意思的事情，就讓我們看看一起來看看它的原理吧。?
其實是生成隨機數，然后改變Form的左上角的坐標。
我用的是循環來弄得，其實可以用timer來控制.

?我把抖動分成了兩種抖動:
1。 生成隨機數，改變窗體左上角坐標，然后立即把窗體的坐上角坐標還原，繼續循環。
2。 生成隨機數，改變窗體左上角坐標，循環完畢之后，然后立即把窗體的坐上角坐標還原。

核心代碼如下：

//第一種抖動
??????? private void button1_Click(object sender, EventArgs e)
??????? {
??????????? int recordx = this.Left;??????????? //保存原來窗體的左上角的x坐標
??????????? int recordy = this.Top;???????????? //保存原來窗體的左上角的y坐標

??????????? Random random = new Random();??????

??????????? for (int i = 0; i < 100; i++)
??????????? {
??????????????? int x = random.Next(rand);
??????????????? int y = random.Next(rand);
??????????????? if (x % 2 == 0)
??????????????? {
??????????????????? this.Left = this.Left + x;
??????????????? }
??????????????? else
??????????????? {
??????????????????? this.Left = this.Left - x;
??????????????? }
??????????????? if (y % 2 == 0)
??????????????? {
??????????????????? this.Top = this.Top + y;
??????????????? }
??????????????? else
??????????????? {
??????????????????? this.Top = this.Top - y;
??????????????? }

??????????????? this.Left = recordx;??????????? //還原原始窗體的左上角的x坐標
??????????????? this.Top = recordy;???????????? //還原原始窗體的左上角的y坐標
??????????? }
???????????
??????? }

??????? //第二種抖動
??????? private void button2_Click(object sender, EventArgs e)
??????? {
??????????? int recordx = this.Left;
??????????? int recordy = this.Top;
??????????? Random random = new Random();
??????????? for (int i = 0; i < 50; i++)
??????????? {
??????????????? int x = random.Next(rand);
??????????????? int y = random.Next(rand);
??????????????? if (x % 2 == 0)
??????????????? {
??????????????????? this.Left = this.Left + x;
??????????????? }
??????????????? else
??????????????? {
??????????????????? this.Left = this.Left - x;
??????????????? }
??????????????? if (y % 2 == 0)
??????????????? {
??????????????????? this.Top = this.Top + y;
??????????????? }
??????????????? else
??????????????? {
??????????????????? this.Top = this.Top - y;
??????????????? }
??????????????? System.Threading.Thread.Sleep(1);
??????????? }
??????????? this.Left = recordx;
??????????? this.Top = recordy;
??????? }

轉載于:https://www.cnblogs.com/gc2013/p/3719339.html

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