求出數組中元素的總和

This program will help to find out the sum of elements in an array which is divisible by a number K. It uses the basic concept of modulo '%' or the remainder of a number.

該程序將幫助找出數組中被數字K整除的元素之和 。 它使用“％”模或數字余數的基本概念。

Program:

程序：

#include<iostream>using namespace std;int main(){int n, ele;cout<<"Enter the size of the array.\n";cin>>n;int A[n];cout<<"Enter elements in the array\n";for(int i =0;i<n;i++){cin>>A[i];}cout<<"Enter the element to be divisible by.\n";cin>>ele;int sum = 0;for(int i =0;i<n;i++){if(A[i]%ele==0){sum += A[i];}}cout<<"The sum is "<<sum<<endl;return 0; }

Output

輸出量

Enter the size of the array. 6 Enter elements in the array 2 3 4 5 6 7 Enter the element to be divisible by. 3 The sum is 9

翻譯自: https://www.includehelp.com/cpp-programs/sum-of-all-the-elements-in-an-array-divisible-by-a-given-number-k.aspx

求出數組中元素的總和

總結

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