共回答了20個問題采納率：75%

clear,clc

format long

f=@(x)[tan(4*3.14*20000*0.03)+2*3.14*20000/x(1)*tan(x(1)*x(2));

sqrt(4*3.14^2*20000^2*7840/2.1e11-log(2)*log(2)/x(2)^2)-x(1)];

[s,v]=fsolve(f,[24;0.1])

Equation solved.

fsolve completed because the vector of function values is near zero

as measured by the default value of the function tolerance,and

the problem appears regular as measured by the gradient.

s =

23.698316600893644

0.132572516762675

v =

1.0e-011 *

0.327282645429250

0

所以就是k1=23.698316600893644,x=0.132572516762675

換用不同的初值會有不同的結果

或者直接用solve

clear,clc

s = solve('tan(4*3.14*20000*0.03)+2*3.14*20000/k1*tan(k1*x)=0',...'k1=sqrt(4*3.14^2*20000^2*7840/2.1e11-log(2)*log(2)/x^2)');

disp('k1='); disp(s.k1); disp('x='); disp(s.x);

1年前

5

總結

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