解題代碼：

粗暴而簡單。大一的水平。?

package com.kyc.liantong;import java.util.Scanner;public class Main {public static void main(String[] args) {Scanner in = new Scanner(System.in);char[] input = in.next().toCharArray();int n = input.length;switch (n) {case 1:StringBuilder sb = new StringBuilder();for (int i = 1; i <= 3; i++) {sb.append(input[0]).append(i).append(" ");}System.out.println(sb.substring(0, sb.length() - 1));break;case 2:StringBuilder sb2 = new StringBuilder();for (int i = 1; i <= 3; i++) {for (int i1 = 1; i1 <= 3; i1++) {sb2.append(input[0]).append(i).append(input[1]).append(i1).append(" ");}}System.out.println(sb2.substring(0, sb2.length() - 1));break;case 3:StringBuilder sb3 = new StringBuilder();for (int i = 1; i <= 3; i++) {for (int i1 = 1; i1 <= 3; i1++) {for (int i2 = 1; i2 <= 3; i2++) {sb3.append(input[0]).append(i).append(input[1]).append(i1).append(input[2]).append(i2).append(" ");}}}System.out.println(sb3.substring(0, sb3.length() - 1));break;case 4:StringBuilder sb4 = new StringBuilder();for (int i = 1; i <= 3; i++) {for (int i1 = 1; i1 <= 3; i1++) {for (int i2 = 1; i2 <= 3; i2++) {for (int i3 = 1; i3 <= 3; i3++) {sb4.append(input[0]).append(i).append(input[1]).append(i1).append(input[2]).append(i2).append(input[3]).append(i3).append(" ");}}}}System.out.println(sb4.substring(0, sb4.length() - 1));break;case 5:StringBuilder sb5 = new StringBuilder();for (int i = 1; i <= 3; i++) {for (int i1 = 1; i1 <= 3; i1++) {for (int i2 = 1; i2 <= 3; i2++) {for (int i3 = 1; i3 <= 3; i3++) {for (int i4 = 1; i4 <= 3; i4++) {sb5.append(input[0]).append(i).append(input[1]).append(i1).append(input[2]).append(i2).append(input[3]).append(i3).append(input[4]).append(i4).append(" ");}}}}}System.out.println(sb5.substring(0, sb5.length() - 1));break;default:}} }

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總結(jié)

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