java stream 多个filter_恕我直言你可能真的不会java第3篇:Stream的Filter与谓词逻辑...
一、基礎代碼準備
建立一個實體類,該實體類有五個屬性。下面的代碼使用了lombok的注解Data、AllArgsConstructor,這樣我們就不用寫get、set方法和全參構造函數了。lombok會幫助我們在編譯期生成這些模式化的代碼。
@Data@AllArgsConstructorpublic class Employee { private Integer id; private Integer age; //年齡 private String gender; //性別 private String firstName; private String lastName;}寫一個測試類,這個測試類的內容也很簡單,新建十個Employee 對象
public class StreamFilterPredicate { public static void main(String[] args){ Employee e1 = new Employee(1,23,"M","Rick","Beethovan"); Employee e2 = new Employee(2,13,"F","Martina","Hengis"); Employee e3 = new Employee(3,43,"M","Ricky","Martin"); Employee e4 = new Employee(4,26,"M","Jon","Lowman"); Employee e5 = new Employee(5,19,"F","Cristine","Maria"); Employee e6 = new Employee(6,15,"M","David","Feezor"); Employee e7 = new Employee(7,68,"F","Melissa","Roy"); Employee e8 = new Employee(8,79,"M","Alex","Gussin"); Employee e9 = new Employee(9,15,"F","Neetu","Singh"); Employee e10 = new Employee(10,45,"M","Naveen","Jain"); List employees = Arrays.asList(e1, e2, e3, e4, e5, e6, e7, e8, e9, e10); List filtered = employees.stream() .filter(e -> e.getAge() > 70 && e.getGender().equals("M")) .collect(Collectors.toList()); System.out.println(filtered); }}需要注意的是上面的filter傳入了lambda表達式(之前的章節我們已經講過了),表達過濾年齡大于70并且男性的Employee員工。輸出如下:
[Employee(id=8, age=79, gender=M, firstName=Alex, lastName=Gussin)]二、什么是謂詞邏輯?
下面要說我們的重點了,通過之前的章節的講解,我們已經知道lambda表達式表達的是一個匿名接口函數的實現。那具體到Stream.filter()中,它表達的是什么呢?看下圖:可以看出它表達的是一個Predicate接口,在英語中這個單詞的意思是:謂詞。
什么是謂詞?(百度百科)
什么是謂詞邏輯?
WHERE 和 AND 限定了主語employee是什么,那么WHERE和AND語句所代表的邏輯就是謂詞邏輯
SELECT *FROM employeeWHERE age > 70AND gender = 'M'三、謂詞邏輯的復用
通常情況下,filter函數中lambda表達式為一次性使用的謂詞邏輯。如果我們的謂詞邏輯需要被多處、多場景、多代碼中使用,通常將它抽取出來單獨定義到它所限定的主語實體中。 比如:將下面的謂詞邏輯定義在Employee實體class中。
public static Predicate ageGreaterThan70 = x -> x.getAge() >70; public static Predicate genderM = x -> x.getGender().equals("M");3.1.and語法(并集)
List filtered = employees.stream() .filter(Employee.ageGreaterThan70.and(Employee.genderM)) .collect(Collectors.toList());輸出如下:
[Employee(id=8, age=79, gender=M, firstName=Alex, lastName=Gussin)]3.2.or語法(交集)
List filtered = employees.stream() .filter(Employee.ageGreaterThan70.or(Employee.genderM)) .collect(Collectors.toList());輸出如下:實際上就是年齡大于70的和所有的男性(由于79的那位也是男性,所以就是所有的男性)
[Employee(id=1, age=23, gender=M, firstName=Rick, lastName=Beethovan), Employee(id=3, age=43, gender=M, firstName=Ricky, lastName=Martin), Employee(id=4, age=26, gender=M, firstName=Jon, lastName=Lowman), Employee(id=6, age=15, gender=M, firstName=David, lastName=Feezor), Employee(id=8, age=79, gender=M, firstName=Alex, lastName=Gussin), Employee(id=10, age=45, gender=M, firstName=Naveen, lastName=Jain)]3.3.negate語法(取反)
List filtered = employees.stream() .filter(Employee.ageGreaterThan70.or(Employee.genderM).negate()) .collect(Collectors.toList());輸出如下:把上一小節代碼的結果取反,實際上就是所有的女性
[Employee(id=2, age=13, gender=F, firstName=Martina, lastName=Hengis), Employee(id=5, age=19, gender=F,面試資料可私聊,Java,資料,面試
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