LeetCode Construct the Rectangle
原題鏈接在這里:https://leetcode.com/problems/construct-the-rectangle/
題目:
For a web developer, it is very important to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:
1. The area of the rectangular web page you designed must equal to the given target area.2. The width W should not be larger than the length L, which means L >= W.
3. The difference between length L and width W should be as small as possible.
You need to output the length L and the width W of the web page you designed in sequence.
Example:
Input: 4 Output: [2, 2] Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. But according to requirement 2, [1,4] is illegal; according to requirement 3, [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.Note:
題解:
從Math.sqrt(area) 開始往下一個一個試width, 看能否讓area被width整除.
Time Complexity: O(Math.sqrt(area)). Space: O(1).
AC Java:
1 public class Solution { 2 public int[] constructRectangle(int area) { 3 if(area == 0){ 4 return new int [] {0,0}; 5 } 6 int w = (int)Math.sqrt(area); 7 while(area%w != 0){ 8 w--; 9 } 10 return new int [] {area/w, w}; 11 } 12 }?
轉載于:https://www.cnblogs.com/Dylan-Java-NYC/p/6360846.html
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