php怎么定义索引,PHP未定义的索引/变量
我使用以下代碼得到以下錯(cuò)誤:
注意:未定義的變量:第35行的C:\ xampp \ htdocs \ test \ projects \ Learning \ php \ Databases \ Forms和Databases \ project.php中的錯(cuò)誤
代碼:
$clicked = false;
if($clicked == false && isset($_POST['submit'])) {
if ($_POST['label'] == '') {
echo "
You must enter in a label!
";$error = true;
}
if ($_POST['url'] == '') {
echo "
You must enter in a url!
";$error = true;
}
if ($_POST['status'] == '') {
echo "
You must enter in a status (0 or 1)!
";$error = true;
}
}
if ($error != true) {
if (isset($_POST['submit']) && $_POST['submit'] == '1' ) {
$query = "INSERT INTO nav (label, url, target, status, position) VALUES ('$_POST[label]', '$_POST[url]', '$_POST[target]', $_POST[status], $_POST[position])";
$result = mysqli_query($dbc, $query);
if ($result) {
echo "
You've added a new navigation link!
";}
else {
echo "
An error has occured!
";echo mysqli_error($dbc);
echo '
'.$query.'
';}
$clicked = true;//submit button replaced
}
}
?>
Navigation
*Required Fields
*Label:
Position:
*URL:
Target:
*Status:
if ($clicked == false) {
echo '
Add Navigation Link
';}
else {
echo '
Do Another
';}
?>
當(dāng)我做出以下更改時(shí):
if($clicked == false && $_POST['submit'] == "1") {
if ($_POST['label'] == '') {
echo "
You must enter in a label!
";$error = true;
}
if ($_POST['url'] == '') {
echo "
You must enter in a url!
";$error = true;
}
if ($_POST['status'] == '') {
echo "
You must enter in a status (0 or 1)!
";$error = true;
}
}
我收到這些錯(cuò)誤:
注意:未定義的索引:在第18行的C:\ xampp \ htdocs \ test \ projects \ Learning \ php \ Databases \ Forms和Databases \ project.php中提交
&
注意:未定義的變量:第35行的C:\ xampp \ htdocs \ test \ projects \ Learning \ php \ Databases \ Forms和Databases \ project.php中的錯(cuò)誤
很明顯,名稱(chēng)“提交”的按鈕不會(huì)因任何原因被“看到”;我相信 . 這對(duì)我來(lái)說(shuō)有點(diǎn)意義,有點(diǎn)......如果我沒(méi)有弄錯(cuò):php從頭到尾以線性方式讀取,并且因?yàn)楸韱卧趇f語(yǔ)句之下,所以索引還不存在 . 我認(rèn)為這進(jìn)一步證實(shí)了這樣一個(gè)事實(shí):一旦我單擊提交按鈕,所有錯(cuò)誤都會(huì)消失,因此執(zhí)行if語(yǔ)句中的if語(yǔ)句的錯(cuò)誤(echo)語(yǔ)句 .
這令人難以置信 . 這也不起作用......
if(isset($_POST['submit']) && $_POST['submit'] == '1') {
if (isset($_POST['label']) && $_POST['label'] == '') {
echo "
You must enter in a label!
";$error = true;
}
if (isset($_POST['url']) && $_POST['url'] == '') {
echo "
You must enter in a url!
";$error = true;
}
if (isset($_POST['status']) && $_POST['status'] == '') {
echo "
You must enter in a status (0 or 1)!
";$error = true;
}
}
...在以前版本的代碼中,isset和"is equal to"的組合用于if語(yǔ)句's conditions, solved the Unidentified index problem, as it pertained to the $_POST[' submit '], here' s代碼:ps:因?yàn)樗鼘儆谶@個(gè)特定的代碼塊,以下鏈接的伙伴tutorial盡管我和他做了完全相同的事情,但我正在跟隨它,并沒(méi)有出現(xiàn)任何這些錯(cuò)誤 .
$clicked = false;
if (isset($_POST['submit']) && $_POST['submit'] == '1' ) {
$query = "INSERT INTO nav (label, url, target, status, position) VALUES ('$_POST[label]', '$_POST[url]', '$_POST[target]', $_POST[status], $_POST[position])";
$result = mysqli_query($dbc, $query);
if ($result) {
echo "
You've added a new navigation link!
";}else {
echo "
An error has occured!
";echo mysqli_error($dbc);
echo '
'.$query.'
';}
$clicked = true;//submit button replaced
}
?>
Navigation
*Required Fields
*Label:
Position:
*URL:
Target:
*Status:
if ($clicked == false) {
echo '
Add Navigation Link
';}
else {
echo '
Do Another
';}
?>
再次,這工作得很好,沒(méi)有錯(cuò)誤 . 那么為什么我在我發(fā)布的第一個(gè)代碼塊中得到了undefine變量錯(cuò)誤?未定義的變量是由于后續(xù)的if語(yǔ)句未能執(zhí)行而導(dǎo)致的,這就是我假設(shè)與索引問(wèn)題有關(guān)的問(wèn)題,但是,錯(cuò)誤并沒(méi)有反映出來(lái)!
當(dāng)我用$ clicked == false替換條件時(shí),如下所示:
$clicked = false;
if($clicked == false) {
if ($_POST['label'] == '') {
echo "
You must enter in a label!
";$error = true;
}
if ($_POST['url'] == '') {
echo "
You must enter in a url!
";$error = true;
}
if ($_POST['status'] == '') {
echo "
You must enter in a status (0 or 1)!
";$error = true;
}
}
我得到了這三個(gè)未定義的索引錯(cuò)誤ALONG WITH BLOODY CODE,它顯然成功執(zhí)行,盡管三個(gè)索引被認(rèn)為是未定義的:
注意:未定義的索引:第20行的C:\ xampp \ htdocs \ test \ projects \ Learning \ php \ Databases \ Forms和Databases \ project4.php中的標(biāo)簽?zāi)仨気斎霕?biāo)簽!
注意:未定義的索引:第24行的C:\ xampp \ htdocs \ test \ projects \ Learning \ php \ Databases \ Forms和Databases \ project4.php中的url你必須輸入一個(gè)url!
注意:未定義的索引:第28行的C:\ xampp \ htdocs \ test \ projects \ Learning \ php \ Databases \ Forms和Databases \ project4.php中的狀態(tài)您必須輸入狀態(tài)(0或1)!
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