1、一維數(shù)組直接合并
?????? 題目：
?????????? 數(shù)組work1[x1,x2——,xn]，work2[y1,y2——,yn]，現(xiàn)在要生成一個數(shù)組work3，
?????? work3中的數(shù)據(jù)為[x1,x2,x3--xn,y1,y2--yn];

?????? 合并方法：
?????????? 直接將兩個矩陣合并：
???????????? A = [1,2,3,4];
???????????? B = [-1,-2,-3,-4];
???????????? C = zeros(1,size(B,2)+size(A,2));???? %這句可以不要;
???????????? C = [A, B];

??? 2、一維數(shù)組交叉合并：
?????? 題目：
?????????? 數(shù)組work1[x1,x2——,xn]，work2[y1,y2——,yn]，現(xiàn)在要生成一個數(shù)組work3，
?????? work3中的數(shù)據(jù)為[x1,y1,x2,y2——,xn,yn];
???? ?
?????? 合并方法一:
?????????? A = [1,2,3,4];
?????????? B = [-1,-2,-3,-4];
?????????? C = zeros(1,size(B,2)+size(A,2));
?????????? C(1:2:end) = A;
?????????? C(2:2:end) = B
???????? ?
?????????? C =
??????????????? 1??? -1???? 2??? -2???? 3??? -3???? 4??? -4

?????? 解法二：
?????????? A = [1,2,3,4];
?????????? B = [-1,-2,-3,-4];
?????????? C=[A' B']';
?????????? C=reshape(C, 1, length(A)+length(B));
???????? ?
?????????? C =
??????????????? 1??? -1???? 2??? -2???? 3??? -3???? 4??? -4

?

?????? 解法三：

?????????? 對于解法二改進：

?????????? c=reshape([A;B],1,[])；

?????????? 這里要注意，只能在v7以上的版本才能使用此法；

?

?????? 解法四：
?????????? A = [1,2,3,4];
?????????? B = [-1,-2,-3,-4];
?????????? C=kron(A,[1 0])+kron(B,[0 1]);
???????? ?
?????????? C =
??????????????? 1??? -1???? 2??? -2???? 3??? -3???? 4??? -4
????? 很多技巧，試總結(jié)以上的方案：
????????? -------------------------------------
????????? A = [1,2,3,4];
????????? B = [-1,-2,-3,-4];
????????? ----------------- 1 -----------------
????????? C = zeros(1,size(B,2)+size(A,2));
????????? C(1:2:end) = A;
????????? C(2:2:end) = B;
????????? C=C(:);
????????? ------------------2 -----------------
????????? C=[A' B']';
????????? C=reshape(C, 1, length(A)+length(B));
????????? ------------------3-------------------
????????? c=reshape([A;B],1,[])
????????? ------------------4-------------------
????????? C=kron(A,[1 0])+kron(B,[0 1]);
????????? --------------------------------------

總結(jié)

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