如何：實現 Windows Communication Foundation 服務協定

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實現 WCF 服務協定

創建一個新 CalculatorService 類，該類從用戶定義的 ICalculator 接口繼承而來并實現該接口定義的協定功能。

實現每個算術運算符的功能。

示例

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using?System;
using?System.ServiceModel;

namespace?Microsoft.ServiceModel.Samples
{
????//?Define?a?service?contract.
????[ServiceContract(Namespace?=?"http://Microsoft.ServiceModel.Samples")]
????public?interface?ICalculator
????{
????????[OperationContract]
????????double?Add(double?n1,?double?n2);
????????[OperationContract]
????????double?Subtract(double?n1,?double?n2);
????????[OperationContract]
????????double?Multiply(double?n1,?double?n2);
????????[OperationContract]
????????double?Divide(double?n1,?double?n2);
????}

????//?Step?1:?Create?service?class?that?implements?the?service?contract.
????public?class?CalculatorService?:?ICalculator
????{
?????????//?Step?2:?Implement?functionality?for?the?service?operations.
????????public?double?Add(double?n1,?double?n2)
????????{
????????????double?result?=?n1?+?n2;
????????????Console.WriteLine("Received?Add({0},{1})",?n1,?n2);
????????????//?Code?added?to?write?output?to?the?console?window.
????????????Console.WriteLine("Return:?{0}",?result);
????????????return?result;
????????}

????????public?double?Subtract(double?n1,?double?n2)
????????{
????????????double?result?=?n1?-?n2;
????????????Console.WriteLine("Received?Subtract({0},{1})",?n1,?n2);
????????????Console.WriteLine("Return:?{0}",?result);
????????????return?result;
????????}

????????public?double?Multiply(double?n1,?double?n2)
????????{
????????????double?result?=?n1?*?n2;
????????????Console.WriteLine("Received?Multiply({0},{1})",?n1,?n2);
????????????Console.WriteLine("Return:?{0}",?result);
????????????return?result;
????????}

????????public?double?Divide(double?n1,?double?n2)
????????{
????????????double?result?=?n1?/?n2;
????????????Console.WriteLine("Received?Divide({0},{1})",?n1,?n2);
????????????Console.WriteLine("Return:?{0}",?result);
????????????return?result;
????????}
????}
}

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創建和實現了服務協定后，創建 WCF 服務的下一步是運行該服務。 運行服務由三個步驟組成：配置、承載和打開服務。

轉載于:https://www.cnblogs.com/tomkillua/archive/2008/09/24/1298212.html

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