java接收遠程調用的數據，得到的是如上個數的返回內容，我怎么寫才能獲取到值，現在使用的請求方法如下：

public static HttpResult postJsonData(String url, Map params, String charset) throws Exception{

CloseableHttpClient httpclient = HttpClientUtil.createDefault();

HttpPost httpPost = new HttpPost(url);

//拼接參數

List list = new ArrayList();

for (Map.Entry entry : params.entrySet()) {

String key = entry.getKey().toString();

String value = entry.getValue().toString();

System.out.println("key=" \+ key + " value=" \+ value);

NameValuePair pair = new BasicNameValuePair(key, value);

list.add(pair);

}

CloseableHttpResponse response=null;

try {

if(StringUtils.isEmpty(charset)){

charset = DEFAULT\_CHARSET;

}

httpPost.setEntity(new UrlEncodedFormEntity(list,charset));

response = httpclient.execute(httpPost);

/\*\*請求發送成功，并得到響應\*\*/

if(response!=null && response.getStatusLine().getStatusCode() == HttpStatus.SC\_OK){

HttpEntity httpEntity = response.getEntity();

if (httpEntity!=null){

System.out.println("響應內容為:" \+ EntityUtils.toString(httpEntity));

//System.out.println("響應內容為1:" + httpEntity.getContent());

}

String result=null;

try {

result = EntityUtils.toString(httpEntity,DEFAULT\_CHARSET);

logger.info(result);

} catch (IOException e) {

throw e;

} finally {

EntityUtils.consume(httpEntity);

}

return JSON.parseObject(result,HttpResult.class);

//return httpEntity.getContent();

}else{

return null;

}

} catch (IOException e) {

throw new Exception(e.getMessage());

}finally {

try{

// 釋放資源

if(response!=null){

response.close();

}

if(httpclient!=null){

httpclient.close();

}

}catch (IOException e1){

throw new Exception("CloseableHttpResponse close exception");

}

}

}

求教怎么寫才能把返回的值取到，現在用上邊的方法會報如下錯誤：

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