問題描述：

Given a List of words, return the words that can be typed using letters of?alphabet?on only one row's of American keyboard like the image below.

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Example 1:

Input: ["Hello", "Alaska", "Dad", "Peace"] Output: ["Alaska", "Dad"]

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Note:

You may use one character in the keyboard more than once.

You may assume the input string will only contain letters of alphabet.

解法一：

常規解法，用unordered_set存儲每一行的字母，依次尋找判斷。

1 class Solution { 2 public: 3 vector<string> findWords(vector<string>& words) { 4 unordered_set<char> row1 {'q', 'w', 'e', 'r', 't', 'y','u', 'i', 'o', 'p'}; 5 unordered_set<char> row2 {'a', 's', 'd', 'f', 'g', 'h', 'j', 'k', 'l'}; 6 unordered_set<char> row3 { 'z', 'x', 'c', 'v', 'b' ,'n', 'm'}; 7 vector<unordered_set<char>> rows {row1, row2, row3}; 8 9 10 vector<string> validWords; 11 for(int i=0; i<words.size(); ++i){ 12 int row=0; 13 14 for(int k=0; k<3; ++k){ 15 if(rows[k].count((char)tolower(words[i][0])) > 0) row = k; 16 } 17 18 validWords.push_back(words[i]); 19 for(int j=1; j<words[i].size(); ++j){ 20 if(rows[row].count((char)tolower(words[i][j])) == 0){ 21 validWords.pop_back(); 22 break; 23 } 24 } 25 26 } 27 return validWords; 28 } 29 };

解法二：

這種解法比較有啟發性，看起來很有意思。

1 class Solution { 2 public: 4 vector<string> findWords(vector<string>& words) 5 { 6 vector<string> res; 7 8 for(auto str : words) 9 { 10 bool r1 = str.find_first_of("QWERTYUIOPqwertyuiop") == string::npos ? false : true; 11 bool r2 = str.find_first_of("ASDFGHJKLasdfghjkl") == string::npos ? false : true; 12 bool r3 = str.find_first_of("ZXCVBNMzxcvbnm") == string::npos ? false : true; 13 14 if(r1 + r2 + r3 == 1) 15 res.push_back(str); 16 } 17 18 return res; 19 } 20 21 };

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轉載于:https://www.cnblogs.com/SarahLiu/p/6702364.html

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