hibernate -- HQL语句总结
生活随笔
收集整理的這篇文章主要介紹了
hibernate -- HQL语句总结
小編覺得挺不錯的,現在分享給大家,幫大家做個參考.
1. 查詢整個映射對象所有字段
| //直接from查詢出來的是一個映射對象,即:查詢整個映射對象所有字段?? ????????String hql = "from Users";?? ????????Query query = session.createQuery(hql);?? ???????????? ????????List<Users> users = query.list();?? ????????for(Users user : users){?? ????????????System.out.println(user.getName() + " : "?+ user.getPasswd() + " : "?+ user.getId());?? ????????}?? ??? ?輸出結果為:?? name1 : password1 : 1? name2 : password2 : 2? name3 : password3 : 3? |
2.查詢字段
| //查詢其中幾個字段?? ????????String hql = " select name,passwd from Users";?? ????????Query query = session.createQuery(hql);?? ????????//默認查詢出來的list里存放的是一個Object數組?? ????????List<Object[]> list = query.list();?? ????????for(Object[] object : list){?? ????????????String name = (String)object[0];?? ????????????String passwd = (String)object[1];?? ???????????????? ????????????System.out.println(name + " : "?+ passwd);?? ????????}?? 輸出結果為:?? name1 : password1?? name2 : password2?? name3 : password3? |
?
3.修改默認查詢結果(query.list())不以Object[]數組形式返回,以List形式返回
| //查詢其中幾個字段,添加new list(),注意list里的l是小寫的。也不需要導入包,這樣通過query.list()出來的list里存放的不再是默認的Object數組了,而是List集合了? ?????????String hql = " select new list(name,passwd) from Users";?? ????????Query query = session.createQuery(hql);?? ????????//默認查詢出來的list里存放的是一個Object數組,但是在這里list里存放的不再是默認的Object數組了,而是List集合了?? ????????List<List> list = query.list();?? ????????for(List user : list){?? ????????????String name = (String)user.get(0);?? ????????????String passwd = (String)user.get(1);?? ???????????????? ????????????System.out.println(name + " : "?+ passwd);?? ????????}?? ????????/**? ????????輸出結果為:? ?????????name1 : password1? ????????name2 : password2? ????????name3 : password3? ?????????*/? |
?
4.修改默認查詢結果(query.list())不以Object[]數組形式返回,以Map形式返回
| //查詢其中幾個字段,添加new map(),注意map里的m是小寫的。也不需要導入包,這樣通過query.list()出來的list里存放的不再是默認的Object數組了,而是map集合了?? ????????String hql = " select new map(name,passwd) from Users";?? ????????Query query = session.createQuery(hql);?? ????????//默認查詢出來的list里存放的是一個Object數組,但是在這里list里存放的不再是默認的Object數組了,而是Map集合了?? ????????List<Map> list = query.list();?? ????????for(Map user : list){?? ????????????//一條記錄里所有的字段值都是map里的一個元素,key是字符串0,1,2,3....,value是字段值?? ????????????//如果將hql改為:String hql = " select new map(name as username,passwd as password) from Users";,那么key將不是字符串0,1,2...了,而是"username","password"了?? ????????????String name = (String)user.get("0");//get("0");是get(key),注意:0,1,2...是字符串,而不是整形?? ????????????String passwd = (String)user.get("1");?? ???????????????? ????????????System.out.println(name + " : "?+ passwd);?? ????????}?? ????????/**? ????????輸出結果為:? ?????????name1 : password1? ????????name2 : password2? ????????name3 : password3? ?????????*/? |
?
5.修改默認查詢結果(query.list())不以Object[]數組形式返回,以自定義類型返回
?
6.條件查詢
| //條件查詢,參數索引值從0開始,索引位置。通過setString,setParameter設置參數?? ????????String hql = "from Users where name=? and passwd=?";?? ????????Query query = session.createQuery(hql);?? ????????//第1種方式?? //????? query.setString(0, "name1");?? //????? query.setString(1, "password1");?? ????????//第2種方式?? ????????query.setParameter(0, "name1",Hibernate.STRING);?? ????????query.setParameter(1, "password1",Hibernate.STRING);?? ????????List<Users> list = query.list();?? ????????for(Users users : list){?? ????????????System.out.println(users.getId());?? ????????}?? |
?
| //條件查詢,自定義索引名(參數名):username,:password.通過setString,setParameter設置參數?? ????????String hql = "from Users where name=:username and passwd=:password";?? ????????Query query = session.createQuery(hql);?? ????????//第1種方式?? //????? query.setString("username", "name1");?? //????? query.setString("password", "password1");?? ????????//第2種方式,第3個參數確定類型?? ????????query.setParameter("username", "name1",Hibernate.STRING);?? ????????query.setParameter("password", "password1",Hibernate.STRING);?? ????????List<Users> list = query.list();?? ????????for(Users users : list){?? ????????????System.out.println(users.getId());?? ????????}? |
| //條件查詢,通過setProperties設置參數?? ????????String hql = "from Users where name=:username and passwd=:password";?? ????????Query query = session.createQuery(hql);?? ????????//MyUser類的2個屬性必須和:username和:password對應?? ????????MyUser myUser = new?MyUser("name1","password1");?? ????????query.setProperties(myUser);?? ????????List<Users> list = query.list();?? ????????for(Users users : list){?? ????????????System.out.println(users.getId());?? ????????}? |
7.update 數據
?????????? 執行SQL語句(為什么要用SQL語句,我想是為了執行某些復雜的SQL語句吧)
| String sql="update Table set field = 'test'" Session session = HibernateSessionFactory.getSession(); session.createSQLQuery(sql).executeUpdate(); ts.commit(); |
?
?????
?? 執行HQL語句
| String hql="update Table set field = 'test'" |
| Session session = HiberanteSessionFactory.getSession(); Transaction ts = session.beginTransaction(); Query query = session.createQuery(hql); query.executeUpdate(); ts.commit(); |
轉載于:https://www.cnblogs.com/printN/p/6415377.html
總結
以上是生活随笔為你收集整理的hibernate -- HQL语句总结的全部內容,希望文章能夠幫你解決所遇到的問題。
- 上一篇: js简单的下拉选中效果
- 下一篇: UVA - 11584 Partitio