city=["北京","上海","天津","重慶"]
puts city
city=Array.new
city[0]="北京"
city[1]="上海"
city[2]="天津"
city[3]="重慶"
puts city

city=["北京","上海","天津","重慶"]
city[4]="香港"
puts "數組的長度為："+city.size.to_s
puts city
puts "第二個元素為："+city[1]
puts "最后一個元素為："+city[-1]

city=Array.new
city[2]="香港"
puts "數組的長度為："+city.size.to_s
puts city

str="深圳"
city_1=%W{北京 上海 天津 重慶 杭州 南京 #{str}}#使用%W{...}進行轉換
puts city_1.size
puts city_1
city_2=%w{北京 上海 天津 重慶 杭州 南京 #{str}}#使用%w{...}進行轉換
puts city_2

college=["北京大學","清華大學"]
college.unshift("浙江大學","復旦大學")??? #向數組頭部添加元素列表
college.push("南京大學","武漢大學")?????? #向數組尾部添加元素列表
college<<"南開大學"?????????????????????? #向數組尾部添加一個元素
puts college.size.to_s
puts college
puts college.pop????????????????????????? #刪除并獲取數組最后一個元素
puts college.shift????????????????????? #刪除并獲取數組第一個元素
puts college.size.to_s
puts college
puts college[2,3]?????????????????????? #截取從索引2開始，長度為3的元素列表
puts college[2..3]????????????????????? #截取從索引2開始，到索引3的元素列表
puts college[2...3]???????????????????? #截取從索引2開始，到索引3(不包括)的元素列表

city_1=["北京","上海","天津"]
city_2=["重慶","香港"]
city_3=city_1+city_2
puts city_3.size.to_s
city_1.concat(city_2)
puts city_1.size.to_s

a=Array.new
p a

a=Array.new(5)
p a

a=Array.new(5,0)
p a
#lang=%W(a b c)
lang=%W{a b c}
p lang

h={"a"=>"b","c"=>"d"}
p h.to_a

s="ab cd efg"
a=s.split(" ")
p a
#p a.include?("ab")
#a.each_with_index do |b,i|
#? p b
#? p i
#end
#h = {:aaa => "bbb", :ccc => "ddd"}
#h.each_key do |key|
#? p h[key]
#end
#h.replace({:a => "b", :c => "d"})
#p h
#t = Time.now
#p t.strftime("%y")

a=[1,2,3,5,7,9]
b=[2,4,6,8,10]
#兩數組相連
p (a+b)
#a數組中的元素減去b數組中與之相同的元素
p (a-b)
#（并集）除去兩個數組中相同的元素
p (a|b)
#（交集）只有兩個數組中都相同的元素
p (p&b)

a=[1,2,3,2]
a.delete(2)?????????? #刪除所有與X相同的元素
p a

a=[1,2,3,2]
a.delete_at(3)??????? #刪除第n個元素
p a

a=[1,2,3,4,5,6,7,8,9,10]
a.slice!(1,5)???????? #刪除數組中第幾到第幾個之間的所有數據
p a

a=[1,2,3,4,5,6,7]
a[1..6]=[4,5,6,7,8,9]?? #a[n..m]方法可以選擇改變數組
p a

a=[1,2,3,4,5,6,7,8,9]
a.each(){|s| p s}
a.each_with_index do |c,i|
?? puts "#{i}? :? #{c}"
? puts (c+i).to_s
end

a=[[1,2],[2,3],[3,4],6]
p a.flatten

s = [ 1, 2, 3 ]?????????? #=> [1, 2, 3]
t = [ 4, 5, 6, [7, 8] ]?? #=> [4, 5, 6, [7, 8]]
a = [ s, t, 9, 10 ]?????? #=> [[1, 2, 3], [4, 5, 6, [7, 8]], 9, 10]
puts?? a.flatten???????????????? #=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
a = [ 1, 2, [3, [4, 5] ] ]
puts a.flatten(1)????????????? #=> [1, 2, 3, [4, 5]]
puts a.flatten??????????????? #=> [1, 2, 3, 4, 5]

a=[1,1,2,2,3,3]
p a.uniq????????????????????? #去掉重復的元素

arr=[9,8,7,1,2,5,3]
p arr.sort??????????????????? #=> [1, 2, 3, 5, 7, 8, 9]
p arr???????????????????????? #=> [9, 8, 7, 1, 2, 5, 3]
p arr.sort!?????????????????? #=> [1, 2, 3, 5, 7, 8, 9]
p arr???????????????????????? #=> [1, 2, 3, 5, 7, 8, 9]
p arr.sort{|a,b| b<=>a}

?

[]
[nil, nil, nil, nil, nil]
[0, 0, 0, 0, 0]
["a", "b", "c"]
[["c", "d"], ["a", "b"]]
["ab", "cd", "efg"]
[1, 2, 3, 5, 7, 9, 2, 4, 6, 8, 10]
[1, 3, 5, 7, 9]
[1, 2, 3, 5, 7, 9, 4, 6, 8, 10]
false
[1, 3]
[1, 2, 3]
[1, 7, 8, 9, 10]
[1, 4, 5, 6, 7, 8, 9]
1
2
3
4
5
6
7
8
9
0? :? 1
1
1? :? 2
3
2? :? 3
5
3? :? 4
7
4? :? 5
9
5? :? 6
11
6? :? 7
13
7? :? 8
15
8? :? 9
17
[1, 2, 2, 3, 3, 4, 6]
1
2
3
4
5
6
7
8
9
10
1
2
3
4
5
1
2
3
4
5
[1, 2, 3]
[1, 2, 3, 5, 7, 8, 9]
[9, 8, 7, 1, 2, 5, 3]
[1, 2, 3, 5, 7, 8, 9]
[1, 2, 3, 5, 7, 8, 9]
[9, 8, 7, 5, 3, 2, 1]

轉載于:https://www.cnblogs.com/mingforyou/archive/2012/07/30/2615213.html

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