//1.寫一個函數(shù)返回參數(shù)二進制中 1 的個數(shù) #include<stdio.h> int div = 0; //除數(shù) int rem = 0; //余數(shù) int count = 0; //計1 int count_one_bits(unsigned int div) {int con = 0; //商while (div >= 1){con = div / 2;rem = div % 2;div = con;if (1 == rem){++count;}}return 0; } int main() {printf("請輸入一個數(shù)字");scanf("%d", &div);count_one_bits(div);printf("%d", count);return 0; }//2.獲取一個數(shù)二進制序列中所有的偶數(shù)位和奇數(shù)位，分別輸出二進制序列。 #include<stdio.h> int main() {int i = 0;int j = 0;int num = 0;int arr1[16] = { 0 };int arr2[16] = { 0 };printf("請輸入一個數(shù)字:\n");scanf("%d", &num);for (i = 0, j = 0; j < 32; ++i, j += 2){arr1[15 - j / 2] = (num >> j) & 1;arr2[15 - i] = (num >> (2 * i + 1)) & 1;}printf("%d對應(yīng)二進制的偶數(shù)位分別是:\n", num);for (i = 0; i < 16; i++){printf("%d", arr1[i]);}printf("\n");printf("%d對應(yīng)二進制的奇數(shù)位分別是:\n", num);for (i = 0; i < 16; i++){printf("%d", arr2[i]);}printf("\n");return 0; }//3. 輸出一個整數(shù)的每一位 #include<stdio.h> int main() {int i = 0;int num = 0;int arr[32] = { 0 };printf("請輸入一個整數(shù):\n");scanf("%d", &num);for (i = 0; i < 32; ++i){arr[31 - i] = (num >> i) & 1;}printf("%d對應(yīng)的二進制數(shù)字是:", num);for (int i = 0; i < 32; ++i){printf("%d", arr[i]);}printf("\n");return 0; }//4.編程實現(xiàn)： //兩個int（32位）整數(shù)m和n的二進制表達中，有多少個位(bit)不同？ //輸入例子 : //1999 2299 //輸出例子 : 7 int main() {int m = 0;int n = 0;int temp = 0;int count = 0;printf("請分別輸入兩個整數(shù)m,n\n");scanf("%d%d", &m, &n);temp = m ^ n;int i = 0;for (i = 0; i < 32; ++i){if ((temp >> i) & 1)++count;}printf("%d和%d二進制表達式中有%d位不同\n", m, n, count);return 0; }

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