先看一下這篇文章
https://blog.csdn.net/csdn_kou/article/details/81148268

四個人同時買票票，引出線程

#include "head.h" int ticket = 100; void * route(void *arg) {char *id = (char *)arg;while(1){if(ticket>0){usleep(1000);printf("%s sells:%d\n",id,ticket);ticket--;}else{break;}} }int main() {key_t key = ftok (".",1);pthread_t t1,t2,t3,t4;pthread_create(&t1,NULL,route,"thread 1");pthread_create(&t2,NULL,route,"thread 2");pthread_create(&t3,NULL,route,"thread 3");pthread_create(&t4,NULL,route,"thread 4");pthread_join(t1,NULL);pthread_join(t2,NULL);pthread_join(t3,NULL);pthread_join(t4,NULL);return 0; }

四個人搶票，爭的票都賣出負數(shù)了，這在實際中是不可以的

改進：引入互斥量加鎖和解鎖概念

#include "head.h" #include <pthread.h> #include <unistd.h>int ticket = 100; pthread_mutex_t mutex;void * route(void *arg) {char *id = (char *)arg;while(1){pthread_mutex_lock(&mutex);if(ticket>0){usleep(1000);printf("%s sells:%d\n",id,ticket);ticket--;pthread_mutex_unlock(&mutex);}else{break;}}}int main() {key_t key = ftok (".",1);pthread_t t1,t2,t3,t4;pthread_create(&t1,NULL,route,"thread 1");pthread_create(&t2,NULL,route,"thread 2");pthread_create(&t3,NULL,route,"thread 3");pthread_create(&t4,NULL,route,"thread 4");pthread_join(t1,NULL);pthread_join(t2,NULL);pthread_join(t3,NULL);pthread_join(t4,NULL);return 0; }

這是我們發(fā)現(xiàn)票是賣的剛剛好，可是卡在那里了。

因為賣完最后一張票，沒有進入if語句，在else語句中沒有解鎖，特別注意的是，用一次
pthread_mutex_lock(&mutex);
就必須在任何有可能退出的地方進行解鎖
pthread_mutex_unlock(&mutex);
改進之后就剛剛好

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