c ++ stl

There are two methods to implement it...

有兩種方法可以實現(xiàn)它...

1 ) by assigning the existing list direct to the new list

1)通過直接將現(xiàn)有列表分配給新列表

list<int> list2 = list1;

2 ) by using list::assign() function

2)通過使用list :: assign()函數(shù)

list<int> list2;list2.assign(list1.begin(), list1.end());

Example:

例：

In this example, we have a list list1 with 10 elements and we are creating another list list2, the elements of list2 will be assigning through the list1 by using list:assign() function, which is a library function of "list header". And, we are also creating a list list3 that is going to be assigned directly through the list1.

在這個例子中，我們有具有10個元素的列表list1的和我們正在創(chuàng)建另一個列表list2中 ，list2中的元素將通過使用列表中的列表1被分配：分配()函數(shù)，該函數(shù)是“列表頭”的庫函數(shù)。 并且，我們還創(chuàng)建了一個列表list3 ，它將直接通過list1進行分配。

Program:

程序：

#include <iostream> #include <list> using namespace std;//function to display the list void dispList(list<int> L) {//declaring iterator to the listlist<int>::iterator l_iter;for (l_iter = L.begin(); l_iter != L.end(); l_iter++)cout<< *l_iter<< " ";cout<<endl; }int main() {//list1 declarationlist<int> list1 = {10, 20, 30, 40, 50, 60, 70, 80, 90, 100};//displaying list1cout<<"Size of list1: "<<list1.size()<<endl;cout<<"Elements of list1: ";dispList(list1);//declaring list2 and assigning the Elements//of list1list<int> list2;list2.assign(list1.begin(), list1.end());//displaying list2cout<<"Size of list2: "<<list2.size()<<endl;cout<<"Elements of list2: ";dispList(list2);//declaring list3 by assigning with list1list<int> list3 = list1;//displaying list3cout<<"Size of list3: "<<list3.size()<<endl;cout<<"Elements of list3: ";dispList(list3);return 0; }

Output

輸出量

Size of list1: 10 Elements of list1: 10 20 30 40 50 60 70 80 90 100 Size of list2: 10 Elements of list2: 10 20 30 40 50 60 70 80 90 100 Size of list3: 10 Elements of list3: 10 20 30 40 50 60 70 80 90 100

翻譯自: https://www.includehelp.com/stl/creating-a-list-by-assigning-the-all-elements-of-another-list.aspx

c ++ stl

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