貝殼形曲線

#http://curvebank.calstatela.edu/naturalcurves/slide7.jpg vertices = 12000t = from 0 to (2*PI)r = 10*(0.7 + 2.6*cos(t) + 1.3*pow(sin(90*t), 3))x = r*sin(t) y = r*cos(t)

魚形曲線

#http://www.2dcurves.com/quartic/quarticfi.html vertices = 1000 t = from 0 to (2*PI) x = cos(t) - sin(t)^2/sqrt(2) y = 0.5*sin(2*t) a = 10 x = x*a y = y*a

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轉(zhuǎn)載于:https://www.cnblogs.com/WhyEngine/p/3844048.html

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