并查集虚拟节点
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HDU 3234 Exclusive-OR
AC代碼簡潔版
AC代碼不好看的
Almost Union-Find UVA - 11987
AC代碼
#include <iostream> #include <cstdio> #include <algorithm> #include <cstring> #include <sstream> using namespace std; typedef long long ll; const int N = 5e5 + 4; const int X = 1e5;int f[N], ans[N], a[1000], n, m; bool dis[1000];void ini(int n); // ans[i] 到根節點的異或值; // a[i] 輸入序列; int find(int u) {if(u == f[u])return u;int t = f[u];f[u] = find(f[u]);ans[u] ^= ans[t];return f[u]; } bool unit(int x,int y,int z) { int a = find(x), b = find(y);if(a == b) return ((ans[x]^ans[y]) != z);if(a == n) swap(a,b);f[a] = b;ans[a] = ans[x]^ans[y]^z;return 0; } int Q(int len) {int an = 0;for(int i = 1;i < len;i ++)dis[i]=0;for(int i = 1;i < len;i ++){if(dis[i]) continue;int t = find(a[i]), cnt = 0;for(int j = i;j < len;j ++)if(find(a[j]) == t){dis[j] = 1; cnt++;an ^= ans[a[j]];}if(cnt%2 == 1&&t != n)return -1;}return an; }int main() {int TESTnum = 1;while(~scanf("%d%d", &n, &m)){if(!n && !m) break;printf("Case %d:\n",TESTnum++);char op[20];int Inum = 0, flag =0 , len;ini(n);while(m --){scanf("%s",op);int an = 0;if(op[0]=='I'){Inum ++; int u, v, w, space = 0;getchar(); gets(op);for(int i = 0;i < strlen(op);i ++)space += (op[i]==' ');if(space == 1) sscanf(op,"%d%d", &u, &w), v = n;else sscanf(op,"%d%d%d", &u, &v, &w);if(flag) continue; if(unit(u, v, w))printf("The first %d facts are conflicting.\n",Inum), flag = 1;}else{scanf("%d",&len);len ++;for(int i=1;i<len;i++)scanf("%d",a+i);if(flag) continue;int an = Q(len);if(an == -1)puts("I don't know.");else printf("%d\n", an);}}puts(""); }return 0; } void ini(int n){for(int i = 0;i <= n;i ++) f[i]=i, ans[i]=0; return ;} #include <algorithm> #include <cstring> #include <sstream> using namespace std; typedef long long ll; const int N = 5e5 + 4; int f[N],ans[N],a[1000],n,m; bool dis[1000]; int read_list(int *a); void ini(int n);int find(int u) {if(u==f[u])return u;int t=f[u];f[u]=find(f[u]);ans[u]^=ans[t];return f[u]; } bool unit(int x,int y,int z) { int a=find(x),b=find(y);if(a==b)return ((ans[x]^ans[y])!=z);if(a==n)swap(a,b);f[a]=b;ans[a]=ans[x]^ans[y]^z;return 0; } bool Q(int len,int *a,int &an) {int x[2],idx=0;for(int i=1;i<len;i++)dis[i]=0;for(int i=1;i<len;i++){if(dis[i])continue;int t=find(a[i]);for(int j=i;j<len;j++){if(find(a[j])==t)dis[j]=1,x[idx++]=a[j];if(idx==2)an^=ans[x[0]]^ans[x[1]],idx=0;}if(idx==1){if(find(x[0])!=n)return 1;else an^=ans[x[0]];idx=0;}}return 0; } int main() {int TESTnum=1;while(scanf("%d%d",&n,&m),n&&m){printf("Case %d:\n",TESTnum++);char op[2];int Inum=0,flag=0,q;ini(n);while(m--){scanf("%s",op);int len=read_list(a),an=0;if(flag)continue;if(op[0]=='I'){Inum++; if(len==2)q=unit(a[0],n,a[1]);else q=unit(a[0],a[1],a[2]);if(q)printf("The first %d facts are conflicting.\n",Inum),flag=1;}else{if(Q(len,a,an))puts("I don't know.");else printf("%d\n",an);}}puts("");}return 0; } int read_list(int *a) {string line;if(!getline(cin,line))return false;stringstream ss(line);int n=0,x;while(ss>>x)a[n++]=x;return n; } void ini(int n) {for(int i=0;i<=n;i++)f[i]=i,ans[i]=0;return ;}?
//201912-3 化學方程式 #include<iostream> #include<cstdio> #include<algorithm> #include<cstring> #include<queue> using namespace std; typedef long long LL; typedef pair<int,int> PII; const int N = 1e5+10, m = 6e4+10, mod = 998244353;int x[N], fa[N], siz[N]; LL val[N];int find(int u){if(u!=fa[u])fa[u]=find(fa[u]);return fa[u];}void merge(int a,int f) {int A = a,b;scanf("%d",&b);a = find(x[a]); b = find(x[b]);if(a == b)return ;if(f&1)fa[a] = b, siz[b] += siz[a], val[b] += val[a];else x[A]=b, siz[a] --, val[a] -= A, val[b] += A, siz[b] ++; } int main() {int n, m;while(~scanf("%d%d",&n, &m)){for(int i = 1;i <= n;i ++)x[i] = fa[i] = val[i] = i, siz[i] = 1;while(m --){int f, p, q;scanf("%d%d",&f,&p);if(f == 3)printf("%d %lld\n",siz[find(x[p])], val[find(x[p])]);else merge(p,f);}}return 0; }總結
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