1、題目

Given a non-negative integer?num, repeatedly add all its digits until the result has only one digit.

For example:

Given?num = 38, the process is like:?3 + 8 = 11,?1 + 1 = 2. Since?2?has only one digit, return it.

2、代碼實現

public class Solution {public int getAllSum(int val) {int sum = 0;while (val > 0) {sum += val % 10;val /= 10;}return sum;}public int addDigits(int num) {if (num <= 0) return 0;while (num >= 10) {num = getAllSum(num);}return num;} }
?

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總結

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