wxpython bind自定义_wxPython的 - 如何从自定义对话框WX
跟進的問題,我已經創建了定制dialog.It會彈出當我們從另一個函數調用的函數,如果用戶點擊“不要繼續“按鈕在對話框窗口我需要得到真/假值,以確定是否按下特定按鈕,并將該值傳遞給函數調用以進一步處理。
但隨著wx自定義對話框,我不能任何返回值,因為對話框一旦我們按任何按鈕被破壞。
有沒有什么辦法通過按鈕點擊事件從自定義對話框類中獲得返回值,并且即使它被銷毀也可以從類外部訪問。
在此先感謝。
def main():
print "start execution"
ret = getUserInput("Do you want to proceed?")
if ret:
print "proceed"
else:
print "exit"
def getUserInput(msg):
class Busy(wx.Dialog):
def __init__(self, parent, msg):
wx.Dialog.__init__(self, parent, wx.ID_ANY, "Message", size=(420, 200))
self.panel = wx.Panel(self, wx.ID_ANY)
self.label = wx.StaticText(self.panel, label=msg, pos=(20, 20))
self.gauge = wx.Gauge(self.panel, size=(300, 20), pos=(50, 50), style=wx.GA_HORIZONTAL)
self.livelabel = wx.StaticText(self.panel, label="Time to live:", pos=(50, 80))
self.lltime = wx.StaticText(self.panel, label="30", pos=(130, 80))
self.notProceedButton = wx.Button(self.panel, label="Don't proceed", pos=(50, 100))
self.timeoutButton = wx.Button(self.panel, label="Timer Off", pos=(250, 100))
self.notProceedButton.Bind(wx.EVT_BUTTON, self.notProceed)
self.timeoutButton.Bind(wx.EVT_BUTTON, self.OnNoTimeout)
self.Bind(wx.EVT_CLOSE, self.OnQuit)
self.timer = wx.Timer(self)
self.Bind(wx.EVT_TIMER, self.OnTimer, self.timer)
self.lifetimer = wx.Timer(self)
self.Bind(wx.EVT_TIMER, self.OnLifeTimer, self.lifetimer)
self.timer.Start(100)
self.lifetimer.Start(1000)
self.timeoutbutton_pressed = False
self.gauge.SetBackgroundColour(wx.Colour(0, 127, 255, 255)) # Slate Blue
self.gauge.SetRange(100)
self.gauge.SetValue(0)
self.life = 30
self.direction = 1
self.result_text = True
def OnTimer(self, evt): # Update gauge
x = int(self.gauge.GetValue())
if x == 0:
self.direction = 1
elif x == 100:
self.direction = -1
x += self.direction
self.gauge.SetValue(x)
def OnLifeTimer(self, evt): # Update time to live
if self.timeoutbutton_pressed == True:
return
self.life -= 1
self.lltime.SetLabelText(str(self.life))
if self.life < 1:
self.OnQuit(None)
def OnNoTimeout(self, evt): # toggle time to live
if self.timeoutbutton_pressed == False:
self.timeoutbutton_pressed = True
self.timeoutButton.SetLabel("Timer On")
else:
self.timeoutbutton_pressed = False
self.timeoutButton.SetLabel("Timer Off")
def OnQuit(self, event):
self.timer.Stop()
self.lifetimer.Stop()
self.Destroy()
def notProceed(self, event): # return input
self.result_text = False
self.timer.Stop()
self.lifetimer.Stop()
self.Destroy()
app = wx.App()
dlg = Busy(parent = None, msg=msg)
dlg.ShowModal()
return dlg.result_text
2017-03-14
Nithya
總結
以上是生活随笔為你收集整理的wxpython bind自定义_wxPython的 - 如何从自定义对话框WX的全部內容,希望文章能夠幫你解決所遇到的問題。
- 上一篇: 前端技术周刊 2019-01-21:跨端
- 下一篇: 基于java的数据结构学习——动态数组C