postgresql测试题_PostgreSQL练习
學生表 Student
create table Student(Sid varchar(6), Sname varchar(10), Sage datetime, Ssex varchar(10));
insert into Student values('01' , '趙雷' , '1990-01-01' , '男');
insert into Student values('02' , '錢電' , '1990-12-21' , '男');
insert into Student values('03' , '孫風' , '1990-05-20' , '男');
insert into Student values('04' , '李云' , '1990-08-06' , '男');
insert into Student values('05' , '周梅' , '1991-12-01' , '女');
insert into Student values('06' , '吳蘭' , '1992-03-01' , '女');
insert into Student values('07' , '鄭竹' , '1989-07-01' , '女');
insert into Student values('08' , '王菊' , '1990-01-20' , '女')
成績表 SC
create table SC(Sid varchar(10), Cid varchar(10), score decimal(18,1));
insert into SC values('01' , '01' , 80);
insert into SC values('01' , '02' , 90);
insert into SC values('01' , '03' , 99);
insert into SC values('02' , '01' , 70);
insert into SC values('02' , '02' , 60);
insert into SC values('02' , '03' , 80);
insert into SC values('03' , '01' , 80);
insert into SC values('03' , '02' , 80);
insert into SC values('03' , '03' , 80);
insert into SC values('04' , '01' , 50);
insert into SC values('04' , '02' , 30);
insert into SC values('04' , '03' , 20);
insert into SC values('05' , '01' , 76);
insert into SC values('05' , '02' , 87);
insert into SC values('06' , '01' , 31);
insert into SC values('06' , '03' , 34);
insert into SC values('07' , '02' , 89);
insert into SC values('07' , '03' , 98)
課程表 Course
create table Course(Cid varchar(10),Cname varchar(10),Tid varchar(10));
insert into Course values('01' , '語文' , '02');
insert into Course values('02' , '數學' , '01');
insert into Course values('03' , '英語' , '03')
教師表 Teacher
create table Teacher(Tid varchar(10),Tname varchar(10));
insert into Teacher values('01' , '張三');
insert into Teacher values('02' , '李四');
insert into Teacher values('03' , '王五')
練習題:
1.查詢" 01 "課程比" 02 "課程成績高的學生的信息及課程分數
select s.*,score
from sdb."Student" s,sdb.sc
where s.Sid=sc.Sid
and s.Sid in(select a.Sid
from sdb.sc a,sdb.sc b
where a.Sid=b.Sid
and a.score>b.score
and a.Cid='01'
and b.Cid='02');
2.查詢平均成績大于等于 60 分的同學的學生編號和學生姓名和平均成績
select s.Sid,Sname,avg(score)
from sdb.sc,sdb."Student" as s
where s.Sid=sc.Sid
group by s.Sid,Sname
having avg(score)>=60;
3.查詢在 SC 表存在成績的學生信息
select *
from sdb.sc,sdb."Student" as s
where s.Sid=sc.Sid
and sc.score is not null;
4.查詢所有同學的學生編號、學生姓名、選課總數、所有課程的總成績(沒成績的顯示為 null )
select s.Sid,Sname,count(Cid),sum(score)
from sdb."Student" s left join sdb.sc
on s.Sid=sc.Sid
group by s.Sid,Sname;
5.查詢「李」姓老師的數量
select count(Tname)
from sdb.teacher as t
where t.Tname like '李%';
6.查詢學過「張三」老師授課的同學的信息
select *
from sdb."Student" as s,sdb.course as c,sdb.teacher as t,sdb.sc
where s.Sid=sc.Sid
and sc.Cid=c.Cid
and c.Tid=t.Tid
and Tname='張三';
7.查詢沒有學全所有課程的同學的信息
select *
from sdb."Student" as s
where s.Sid in (select sc.Sid from sdb.sc group by sc.Sid having count(Cid)<3 )
select s.Sid
from sdb."Student" as s
left join sdb.sc
on s.Sid=sc.Sid
group by s.Sid
having count(sc.Cid)
8.查詢和" 01 "號的同學學習的課程完全相同的其他同學的信息
select s.Sid,Sname,Sage,Ssex
from sdb."Student" s,sdb.sc
where s.Sid=sc.Sid
and s.Sid !='01'
group by s.Sid,Sname,Sage,Ssex
having count(Cid)=(select count(Cid) from sdb.sc where Sid='01');
9.查詢至少有一門課與學號為" 01 "的同學所學相同的同學的信息
select *
from sdb."Student" s
where Sid in (select Sid
from sdb.sc
where Cid in(select Cid
from sdb.sc
where Sid='01'));
10.查詢沒學過"張三"老師講授的任一門課程的學生姓名
select Sname
from sdb."Student" s
where Sid not in(
select s.Sid
from sdb."Student" as s,sdb.course as c,sdb.teacher as t,sdb.sc
where s.Sid=sc.Sid
and sc.Cid=c.Cid
and c.Tid=t.Tid
and Tname like '張三');
11.查詢兩門及其以上不及格課程的同學的學號,姓名及其平均成績
select s.Sid,Sname,avg(score)
from sdb."Student" s,sdb.sc
where s.Sid=sc.Sid
and s.Sid not in (select distinct Sid
from sdb.sc
where score>=60)
group by s.Sid,Sname;
12.檢索" 01 "課程分數小于 60,按分數降序排列的學生信息
select s.*
from sdb."Student" s,sdb.sc
where s.Sid=sc.Sid
and Cid='01'
and score<60
order by score desc;
13.按平均成績從高到低顯示所有學生的所有課程的成績以及平均成績
select score,avg(score)
from sdb.sc
group by score
order by avg(score) desc;
select Sid,
sum(case when Cid='01' then score else null end) score_01,
sum(case when Cid='02' then score else null end) score_02,
sum(case when Cid='03' then score else null end) score_03,
avg(score)
from sdb.sc
group by Sid
order by avg(score) desc;
14.查詢各科成績最高分、最低分和平均分,以如下形式顯示:課程 ID,課程 name,最高分,最低分,平均分,及格率,中等率,優良率,優秀率(及格為>=60,中等為:70-80,優良為:80-90,優秀為:>=90)。
select sc.Cid ,Cname 課程名稱,avg(score) 平均分,max(score) 最高成績,min(score) 最低成績,
(sum(case when score>=60 then 1 else 0 end)*100/count(score)) 及格率,
(sum(case when score>=70 and score<80 then 1 else 0 end)*100/count(score)) 中等率,
(sum(case when score>=80 and score<90 then 1 else 0 end)*100/count(score)) 良好率,
(sum(case when score>=90 then 1 else 0 end )*100/count(score)) 優秀率
from sdb.sc,sdb.course c
where sc.Cid=c.Cid
group by sc.Cid,Cname
15.統計各科成績各分數段人數:課程編號,課程名稱,[100-85],[85-70],[70-60],[60-0] 及所占百分比
select sc.Cid 課程編號,Cname 課程名稱,
(sum(case when score>=0 and score<=60 then 1 else 0 end)*1.00/count(score)) as 不及格0_60,
(sum(case when score>60 and score<=70 then 1 else 0 end)*1.00/count(score)) as 及格60_70,
(sum(case when score>70 and score<=85 then 1 else 0 end)*1.00/count(score)) as 良好70_85,
(sum(case when score>85 and score<=100 then 1 else 0 end)*1.00/count(score)) as 優秀85_100
from sdb.sc,sdb.course c
where sc.Cid=c.Cid
group by sc.Cid,Cname
16.查詢各科成績前三名的記錄
select Cid,Sid,score
from sdb.sc
where (select count(*)
from sdb.sc a
where a.Cid=sc.Cid
and sc.score>a.score)<3
order by Cid,score desc;
select * from (select *,rank() over(partition by Cid order by score desc) as graderank from sdb.sc) a
where a.graderank <=3;
17. 查詢出只選修兩門課程的學生學號和姓名
select s.Sid,Sname
from sdb."Student" s,sdb.sc
where s.Sid=sc.Sid
group by s.Sid,Sname
having count(Cid)=2;
18.查詢名字中含有「風」字的學生信息
select *
from sdb."Student" s
where Sname like '%風%';
19.成績不重復,查詢選修「張三」老師所授課程的學生中,成績最高的學生信息及其成績
select s.Sid,Sname,Ssex,Sage,score
from sdb."Student" as s,sdb.sc
where s.Sid=sc.Sid
group by s.Sid,Sname,Ssex,Sage,score
having max(score)=(select max(score)
from sdb."Student" as s,sdb.course as c,sdb.teacher as t,sdb.sc
where s.Sid=sc.Sid
and sc.Cid=c.Cid
and c.Tid=t.Tid
and Tname like '張三');
總結
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