python合并列表并按升序排序_在python中按升序合并两个排序的链接列表:单链接列表指针更新问题...
你需要分配
l1
和
l2
tempNode.val
L1
節點本身到
tempNode
# Definition for singly-linked list.
class ListNode:
def __init__(self, x=None):
self.val = x
self.next = None
a = ListNode(5)
b = ListNode(10)
c = ListNode(20)
e = ListNode(0)
f = ListNode(5)
g = ListNode(21)
h = ListNode(30)
a.next = b
b.next = c
e.next = f
f.next = g
g.next = h
class Solution:
def mergeTwoLists(self, l1, l2):
returnNode = tempNode = ListNode()
while l1 or l2:
if not l1:
print('l1 is empty; adding value from l2:', l2.val)
tempNode.val = l2.val
tempNode.next = ListNode()
tempNode = tempNode.next
l2 = l2.next
elif not l2:
print('l2 is empty; adding value from l1:', l1.val)
tempNode.val = l1.val
tempNode.next = ListNode()
tempNode = tempNode.next
l1 = l1.next
elif l1.val < l2.val:
print("l1.val < l2.val", l1.val, l2.val)
tempNode.val = l1.val
tempNode.next = ListNode()
tempNode = tempNode.next
l1 = l1.next
elif l1.val == l2.val:
print("l1.val == l2.val", l1.val, l2.val)
#If both the values are equal, assign l1's value first
#then make l2's value follow l1's value using tempNode
tempNode.val = l1.val
tempNode.next = ListNode() #Because of the previous statement, after execution of this statement, I'm assuming tempNode.val is now l1.val and tempNode.next = l1.next
tempNode = tempNode.next
#tempNode.next is supposed to be equal to l1.next, instead assign it to l2
tempNode.val = l2.val
tempNode.next = ListNode() #Because of the previous statement, after execution of this statement, I'm assuming tempNode.val is now l2.val and tempNode.next = l2.next
tempNode = tempNode.next
#Increment both l1 and l2
l1 = l1.next
l2 = l2.next
else:
print("l1.val > l2.val", l1.val, l2.val)
tempNode.val = l2.val
tempNode.next = ListNode()
tempNode = tempNode.next
l2 = l2.next
return returnNode
sol = Solution()
node = sol.mergeTwoLists(a, e)
while node and node.val is not None:
print(node.val)
node = node.next
l1.val > l2.val 5 0
l1.val == l2.val 5 5
l1.val < l2.val 10 21
l1.val < l2.val 20 21
l1 is empty; adding value from l2: 21
l1 is empty; adding value from l2: 30
0
5
5
10
20
21
30
總結
以上是生活随笔為你收集整理的python合并列表并按升序排序_在python中按升序合并两个排序的链接列表:单链接列表指针更新问题...的全部內容,希望文章能夠幫你解決所遇到的問題。
- 上一篇: python实现qq登录_在django
- 下一篇: linux 句柄_linux 文件句柄数