python如何设置窗口保持显示_如何保持Python脚本输出窗口打开?
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在發(fā)生異常時保持窗口打開(但是,同時打印異常)Python 2if?__name__?==?'__main__':
????try:
????????##?your?code,?typically?one?function?call
????except?Exception:
????????import?sys????????print?sys.exc_info()[0]
????????import?traceback????????print?traceback.format_exc()
????????print?"Press?Enter?to?continue?..."?
????????raw_input()在任何情況下保持窗口打開:if?__name__?==?'__main__':
????try:
????????##?your?code,?typically?one?function?call
????except?Exception:
????????import?sys????????print?sys.exc_info()[0]
????????import?traceback????????print?traceback.format_exc()
????finally:
????????print?"Press?Enter?to?continue?..."?
????????raw_input()Python 3對于Python 3你必須使用input()代替raw_input(),當然也調整了print陳述。if?__name__?==?'__main__':
????try:
????????##?your?code,?typically?one?function?call
????except?BaseException:
????????import?sys????????print(sys.exc_info()[0])
????????import?traceback????????print(traceback.format_exc())
????????print("Press?Enter?to?continue?...")
????????input()在任何情況下保持窗口打開:if?__name__?==?'__main__':
????try:
????????##?your?code,?typically?one?function?callexcept?BaseException:
????import?sys????print(sys.exc_info()[0])
????import?traceback????print(traceback.format_exc())finally:
????print("Press?Enter?to?continue?...")
????input()
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