花两千元学python_花两万学的python,总结了一点初学者的小技巧,免费送给大家...
交換變量
x = 6
y = 5
x, y = y, x
print x
>>> 5
print y
>>> 6
if 語(yǔ)句在行內(nèi)
print "Hello" if True else "World"
>>> Hello
連接
下面的最后一種方式在綁定兩個(gè)不同類型的對(duì)象時(shí)顯得很酷。
nfc = ["Packers", "49ers"]
afc = ["Ravens", "Patriots"]
print nfc + afc
>>> ['Packers', '49ers', 'Ravens', 'Patriots']
print str(1) + " world"
>>> 1 world
print `1` + " world"
>>> 1 world
print 1, "world"
>>> 1 world
print nfc, 1
>>> ['Packers', '49ers'] 1
計(jì)算技巧
#向下取整
print 5.0//2
>>> 2
# 2的5次方
print 2**5
>> 32
注意浮點(diǎn)數(shù)的除法
print .3/.1
>>> 2.9999999999999996
print .3//.1
>>> 2.0
數(shù)值比較
x = 2
if 3 > x > 1:
print x
>>> 2
if 1 < x > 0:
print x
>>> 2
兩個(gè)列表同時(shí)迭代
zip函數(shù)所有條件都滿足時(shí)才會(huì)進(jìn)行循環(huán),任意個(gè)列表遍歷完都會(huì)跳出循環(huán)
nfc = ["Packers", "49ers"]
afc = ["Ravens", "Patriots"]
for teama, teamb in zip(nfc, afc):
print teama + " vs. " + teamb
>>> Packers vs. Ravens
>>> 49ers vs. Patriots
帶索引的列表迭代
teams = ["Packers", "49ers", "Ravens", "Patriots"]
for index, team in enumerate(teams):
print index, team
>>> 0 Packers
>>> 1 49ers
>>> 2 Ravens
>>> 3 Patriots
列表推導(dǎo)
已知一個(gè)列表,刷選出偶數(shù)列表方法:
numbers = [1,2,3,4,5,6]
even = []
for number in numbers:
if number%2 == 0:
even.append(number)
用下面的代替
numbers = [1,2,3,4,5,6]
even = [number for number in numbers if number%2 == 0]
字典推導(dǎo)
teams = ["Packers", "49ers", "Ravens", "Patriots"]
print {key: value for value, key in enumerate(teams)}
>>> {'49ers': 1, 'Ravens': 2, 'Patriots': 3, 'Packers': 0}
初始化列表的值
items = [0]*3
print items
>>> [0,0,0]
將列表轉(zhuǎn)換成字符串
teams = ["Packers", "49ers", "Ravens", "Patriots"]
print ", ".join(teams)
>>> 'Packers, 49ers, Ravens, Patriots'
從字典中獲取元素
不要用下列的方式
data = {'user': 1, 'name': 'Max', 'three': 4}
try:
is_admin = data['admin']
except KeyError:
is_admin = False
替換為
data = {'user': 1, 'name': 'Max', 'three': 4}
is_admin = data.get('admin', False)
獲取子列表
x = [1,2,3,4,5,6]
#前3個(gè)
print x[:3]
>>> [1,2,3]
#中間4個(gè)
print x[1:5]
>>> [2,3,4,5]
#最后3個(gè)
print x[-3:]
>>> [4,5,6]
#奇數(shù)項(xiàng)
print x[::2]
>>> [1,3,5]
#偶數(shù)項(xiàng)
print x[1::2]
>>> [2,4,6]
60個(gè)字符解決FizzBuzz
前段時(shí)間Jeff Atwood 推廣了一個(gè)簡(jiǎn)單的編程練習(xí)叫FizzBuzz,問題引用如下:
寫一個(gè)程序,打印數(shù)字1到100,3的倍數(shù)打印“Fizz”來替換這個(gè)數(shù),5的倍數(shù)打印“Buzz”,對(duì)于既是3的倍數(shù)又是5的倍數(shù)的數(shù)字打印“FizzBuzz”。
這里有一個(gè)簡(jiǎn)短的方法解決這個(gè)問題:
for x in range(101):print"fizz"[x%3*4::]+"buzz"[x%5*4::]or x
集合
用到Counter庫(kù)
from collections import Counter
print Counter("hello")
>>> Counter({'l': 2, 'h': 1, 'e': 1, 'o': 1})
迭代工具
和collections庫(kù)一樣,還有一個(gè)庫(kù)叫itertools
from itertools import combinations
teams = ["Packers", "49ers", "Ravens", "Patriots"]
for game in combinations(teams, 2):
print game
>>> ('Packers', '49ers')
>>> ('Packers', 'Ravens')
>>> ('Packers', 'Patriots')
>>> ('49ers', 'Ravens')
>>> ('49ers', 'Patriots')
>>> ('Ravens', 'Patriots')
False == True
在python中,True和False是全局變量,因此:
False = True
if False:
print "Hello"
else:
print "World"
>>> Hello
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作者:大明白
鏈接:https://www.jianshu.com/p/883db10b506a
來源:簡(jiǎn)書
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