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c模擬，好吧 沒有考慮0為加數(shù)的情況結果wa了

#include <iostream> #include <stdio.h> #include <string.h> using namespace std; int n; char str[120]; int add[120],sum[120]; int flag=0; void fclear(){memset(sum, 0, sizeof(sum)); }void fadd(){int l=strlen(str);//cout<<"l = "<<l<<endl;;int i=0, j=l-1;//cout<<"str[0]"<<str[0]<<endl;for(i=110; i>110-l; i--){add[i]=str[j--]-'0';//cout<<"i add[i] "<<i<<" "<<add[i]<<endl;}for(i=110; i>110-l; i--){//cout<<i<<" "<<sum[i]<<" "<<sum[i-1]<<endl;//cout<<sum[i]<<" + "<<add[i]<<" = "<<sum[i]+add[i]<<" / ";if(sum[i]+add[i]>9){sum[i]=sum[i]+add[i]-10;sum[i-1]++;}else{sum[i]+=add[i];}//cout<<sum[i]<<endl;//cout<<sum[i]<<" "<<sum[i-1]<<endl;} }void fout(){flag=0;for(int i=0; i<=110; i++){if(sum[i]==0 && flag==0){if(i==110 && sum[i]==0){cout<<"0";}continue;}else{cout<<sum[i];flag=1;}}cout<<endl; }int main(){cin>>n;getchar();getchar();getchar();for(int i=0; i<n; i++){fclear();while(1){gets(str);//cout<<endl<<"*"<<str[0]<<"*"<<endl;//cout<<"str="<<str<<endl;if((str[0]=='\0')){//cout<<"*"<<endl;fout();if(i!=n-1){cout<<endl;}break;}else{//cout<<"**"<<endl;fadd();/*cout<<"_____"<<endl;fout();cout<<endl<<"_____"<<endl;*/}}}return 0; }

有java不用就是坑

import java.util.Scanner; import java.math.BigInteger;public class Main {public static void main(String[] args) {Scanner scanner=new Scanner(System.in);int n;BigInteger m,sum;n=scanner.nextInt();for(int i=1;i<=n;i++){sum=BigInteger.ZERO;while(scanner.hasNextBigInteger()){m=scanner.nextBigInteger();if(m.equals(BigInteger.ZERO))break;sum=sum.add(m);}System.out.println(sum);if(i<n)System.out.println();}}}

轉載于:https://my.oschina.net/dianpaopao/blog/162768

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