問(wèn)題是：b) Add to the condition in the while loop so that it will stop if either the user inputs a zero or the sum is larger than limit (if limit is None then ignore the second stopping condition). Do not use a break statement to implement this feature.

底下是我寫的程序，可是運(yùn)行過(guò)程并沒(méi)有按照描述運(yùn)行，有錯(cuò)誤：

def sum_odd_inputs(limit = None):

"""(integer) -> integer

Asks the user to enter a set of integer inputs. The function sums all odd

inputs (it discards all even inputs). The user can indicate that the set is

complete by entering the integer 0. The set will also be considered complete

if the running sum exceeds limit. If limit == None, then only a user input

of zero will complete the set.

>>>sum_odd_inputs()

Enter an integer (0 to quit): 5

Enter an integer (0 to quit): 6

Enter an integer (0 to quit): 10

Enter an integer (0 to quit): 7

Enter an integer (0 to quit): 0

12

>>>sum_odd_inputs(10)

Enter an integer (0 to quit):2

Enter an integer (0 to quit):3

Enter an integer (0 to quit):5

Enter an integer (0 to quit):1

Enter an integer (0 to quit):3

12

"""

set_sum = 0

user_input = raw_input ('Enter an integer (0 to quit):')

def even_number():

user_input%2 == 0

def odd_number():

user_input%2 != 0

while user_input%2 != 0:

if user_input != 0:

set_sum += user_input

elif set_sum <= 10:

set_sum += user_input

return set_sum

總結(jié)

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